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Tresset [83]
3 years ago
14

Evaluate the expression when y = 3 and z = -1/5.

Mathematics
1 answer:
konstantin123 [22]3 years ago
7 0

Answer:

<em>-9/10</em>

Step-by-step explanation:

Plug In: y = 3 z = -1/5

1/2z - 2/3y

Multiply:

1/2(-1/5) - 2/3(3)

Solve:

-1/10 - 2 = -.1 - 2 = -.9 = -9/10

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Each part of a race is 1/10 mile long. Marsha finished 5parts of the race. How far did Marsha race
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3 years ago
HURRY PLEASE!
Goshia [24]

Answer:

Option b.

4x^3y^2\sqrt[3]{4xy}

Step-by-step explanation:

we have the expression

\sqrt[3]{256x^{10}y^{7}}

Remember these properties

\sqrt[n]{x^m} =x^{\frac{m}{n}}

(x^{m})^{n} =x^{m*n}

(x^{m})(x^{n})=x^{m+n}

so

\sqrt[3]{256x^{10}y^{7}}=(256x^{10}y^{7})^{\frac{1}{3}}=(256^{\frac{1}{3}})(x^{\frac{10}{3}})(y^{\frac{7}{3}})

Rewrite the expression

256=(4^3)(2^2)

x^{10}=(x^9)(x)

y^7=(y^6)(y)

substitute

(256x^{10}y^{7})^{\frac{1}{3}}=((4^3)(2^2)(x^9)(x)(y^6)(y))^{\frac{1}{3}}

Applying properties of exponents

((4^3)(2^2)(x^9)(x)(y^6)(y))^{\frac{1}{3}}=(4^3)^{\frac{1}{3}}(2^2)^{\frac{1}{3}}(x^9)^{\frac{1}{3}}(x)^{\frac{1}{3}}(y^6)^{\frac{1}{3}}(y)^{\frac{1}{3}}

simplify

(4)^{\frac{3}{3}}(2)^{\frac{2}{3}}(x)^{\frac{9}{3}}(x)^{\frac{1}{3}}(y)^{\frac{6}{3}}(y)^{\frac{1}{3}}

(4)(2)^{\frac{2}{3}}(x)^{3}(x)^{\frac{1}{3}}(y)^{2}(y)^{\frac{1}{3}}

4x^3y^2\sqrt[3]{4xy}

6 0
3 years ago
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Solve for z : 4z-6/4=3z+1
ruslelena [56]

Note the equal sign, what you do to one side, you do to the other side. Isolate the variable z.

First, subtract 3z and add 6/4 to both sides

4z (-3z) - 6/4 (+6/4) = 3z (-3z) + 1 (+6/4)

4z - 3z = 1 + 6/4

Simplify. Note that 1 = 4/4.

z = 4/4 + 6/4

Simplify. Combine like terms

z = 10/4

Simplify. Change the improper fraction into mixed fraction and simplify.

z = 10/4 = 2 2/4 = 2 1/2

~

7 0
3 years ago
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