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gregori [183]
3 years ago
12

find the 16th term of the arithmetic sequence whose common difference is d=8 and whose first term is a↓1=3​

Mathematics
1 answer:
Softa [21]3 years ago
7 0

Answer:

123

Step-by-step explanation:

3 + (16 - 1)8

3 + (15)8

3 + 120

123

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The following pattern starts with 4 and uses the rule add 6 to the previous term.
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Answer:

Every number in the pattern is greater than the previous number.

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Solve the quadratic equation 3x^2+x-5=0
irinina [24]
-1 <span>± </span><span><span>√61 / 6. Negative 1, plus or minus square root of 61 divide by 6</span></span>
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4 years ago
Solve for the variable a D =a+b-c/3
yuradex [85]
Hey there,
solving for a is just like you think of all other letter as a constant
i.e the only variable is a
so you need to subtract b as a start
      d=a+b-c/3
-b             -b
=============

    -b+d=a-c/3                now it's time to add c/3 (isolate a by itself in one side)

     -b+d=a-c/3
+c/3         +c/3
==============
c/3-b+d=a

Hence you have solved for a




4 0
4 years ago
ΔABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C?
kotykmax [81]

Answer:

cos(C) =\frac{40}{41}\\\\cos(C)=0.976

Step-by-step explanation:

To find the cos (C) we must use the cosine theorem.

The cosine theorem says that:

c^2 = a^2 +b^2 -2abcos(C)

In this case:

c=AB = 9

b=CA = 41

a=BC = 40

So

9^2 = 40^2 +41^2 -2(40)*(41)cos(C)

9^2- 40^2- 41^2 =-2(40)*(41)cos(C)

cos(C) = -\frac{9^2- 40^2- 41^2}{2(40)*(41)}

cos(C) =\frac{40}{41}\\\\cos(C)=0.976

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3 years ago
What number is 80% of 90%?​
storchak [24]
Answering so you can mark the other person brainliest
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