find the 16th term of the arithmetic sequence whose common difference is d=8 and whose first term is a↓1=3
1 answer:
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To answer this question, we have to do the long division process for polynomials. We can do the operation as follows:
To do this division process, we have:
1. Divide the first term of the dividend by the first element of the divisor. They are:
2. Now, we have to multiply this result by the divisor, and the result will change its sign since we have to subtract that result from the dividend as follows:
And since we to subtract this result from the dividend, we end up with:
3. Then we have the following algebraic addition:
4. Again, we need to divide the first term of the dividend by the first term of the divisor as follows:
5. And we have to multiply 5 by the divisor, and the result will be subtracted from the dividend:
Since we have to subtract this from the dividend, we have:
6. And we have to add this algebraically to the dividend we got in the previous step:
And this is the remainder of the division, x + 5.
As we can see from the division process, we got as:
1. The quotient: -x + 5
2. The remainder: x + 5.
Since we have that the dividend = divisor * quotient + remainder.
Therefore, the result for this division is:
