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mihalych1998 [28]
3 years ago
9

What is a like term for 7y​

Mathematics
1 answer:
jonny [76]3 years ago
5 0

Answer:

Step-by-step explanation:

A 'like term' for 7y must have the variable y in it, but would have a different coefficient.  

For example:  11y and 7y are like terms:  same variable, different coefficients.

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Change each of the following points from rectangular coordinates to spherical coordinates and to cylindrical coordinates.
FromTheMoon [43]

Answer and Step-by-step explanation: Spherical coordinate describes a location of a point in space: one distance (ρ) and two angles (Ф,θ).To transform cartesian coordinates into spherical coordinates:

\rho = \sqrt{x^{2}+y^{2}+z^{2}}

\phi = cos^{-1}\frac{z}{\rho}

For angle θ:

  • If x > 0 and y > 0: \theta = tan^{-1}\frac{y}{x};
  • If x < 0: \theta = \pi + tan^{-1}\frac{y}{x};
  • If x > 0 and y < 0: \theta = 2\pi + tan^{-1}\frac{y}{x};

Calculating:

a) (4,2,-4)

\rho = \sqrt{4^{2}+2^{2}+(-4)^{2}} = 6

\phi = cos^{-1}(\frac{-4}{6})

\phi = cos^{-1}(\frac{-2}{3})

For θ, choose 1st option:

\theta = tan^{-1}(\frac{2}{4})

\theta = tan^{-1}(\frac{1}{2})

b) (0,8,15)

\rho = \sqrt{0^{2}+8^{2}+(15)^{2}} = 17

\phi = cos^{-1}(\frac{15}{17})

\theta = tan^{-1}\frac{y}{x}

The angle θ gives a tangent that doesn't exist. Analysing table of sine, cosine and tangent: θ = \frac{\pi}{2}

c) (√2,1,1)

\rho = \sqrt{(\sqrt{2} )^{2}+1^{2}+1^{2}} = 2

\phi = cos^{-1}(\frac{1}{2})

\phi = \frac{\pi}{3}

\theta = tan^{-1}\frac{1}{\sqrt{2} }

d) (−2√3,−2,3)

\rho = \sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}+3^{2}} = 5

\phi = cos^{-1}(\frac{3}{5})

Since x < 0, use 2nd option:

\theta = \pi + tan^{-1}\frac{1}{\sqrt{3} }

\theta = \pi + \frac{\pi}{6}

\theta = \frac{7\pi}{6}

Cilindrical coordinate describes a 3 dimension space: 2 distances (r and z) and 1 angle (θ). To express cartesian coordinates into cilindrical:

r=\sqrt{x^{2}+y^{2}}

Angle θ is the same as spherical coordinate;

z = z

Calculating:

a) (4,2,-4)

r=\sqrt{4^{2}+2^{2}} = \sqrt{20}

\theta = tan^{-1}\frac{1}{2}

z = -4

b) (0, 8, 15)

r=\sqrt{0^{2}+8^{2}} = 8

\theta = \frac{\pi}{2}

z = 15

c) (√2,1,1)

r=\sqrt{(\sqrt{2} )^{2}+1^{2}} = \sqrt{3}

\theta = \frac{\pi}{3}

z = 1

d) (−2√3,−2,3)

r=\sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}} = 4

\theta = \frac{7\pi}{6}

z = 3

5 0
3 years ago
Solve this equation <br><br> 18 = n -18<br><br> n=
Mandarinka [93]

Answer:

n= 36

Step-by-step explanation:

18=n-18 (add 18 to both sides of the equation, 18 and -18 cancel out)

36=n

8 0
2 years ago
Read 2 more answers
Calculate the pay for the following day of a<br> weekly time card given a wage of $12.50/hr.
Elenna [48]

The one day pay is $106.25 rounded to the nearest hundredth.

<u>Step-by-step explanation:</u>

<u>From the table shown :</u>

  • The timing shown in the morning is from 8:00 to 12:15
  • The number of hours worked in the morning = 4 hours 15 minutes.

It is given that, the pay is $12.5 per hour.

Therefore, the pay earned in the morning = No.of hours × pay per hour.

⇒ 4 hours × 12.5 = $50

⇒ (15 mins / 60 mins) × 12.5 = $3.125

⇒ 50+3.125

⇒ 53.125

  • The timing shown in the afternoon is from 8:00 to 12:15
  • The number of hours worked in the morning = 4 hours 15 minutes.

Therefore, the pay earned in the afternoon = No.of hours × pay per hour.

⇒  4 hours × 12.5 = $50

⇒ (15 mins / 60 mins) × 12.5 = $3.125

⇒ 50+3.125

⇒ 53.125

The pay for 1 day = pay earned in the morning section + pay earned in the afternoon section.

⇒ 53.125 + 53.125

⇒ 106.25

∴ The one day pay is $106.25 rounded to the nearest hundredth.

7 0
3 years ago
Solve 1 And 2 Step Equations.
masha68 [24]

Answer:

ksbdksvudkdbckx skxid SORRRYYYYY BUT I NEED POINTSSSSS :(

7 0
2 years ago
Can someone help? 25 points
zavuch27 [327]

Answer:

x= 156

Step-by-step explanation:

i had a test with the same question, i promise its right :)

6 0
3 years ago
Read 2 more answers
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