What is a like term for 7y

Mathematics

1 answer:

jonny [76]4 years ago

5 0

Answer:

Step-by-step explanation:

A 'like term' for 7y must have the variable y in it, but would have a different coefficient.

For example: 11y and 7y are like terms: same variable, different coefficients.

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For the function f(x)=−7x2+8x−8, find f(4).

Jet001 [13]

Answer:

- 88

Step-by-step explanation:

$f(x ) = - 7 {x}^{2} + 8x - 8 \\ plug \: x = 4 \\ \\ \implies \: f(4 ) = - 7 {(4)}^{2} + 8(4) - 8 \\\\ \implies \: f(4 ) = - 7 \times 16 + 32 - 8 \\\\ \implies \: f(4 ) = - 112+ 32 - 8 \\ \\ \implies \: f(4 ) = - 120+ 32 \\\\ \implies \: f(4 ) = - 88 \\$

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2 years ago

There are 7 roses in a vase of 15 flowers. The rest are daises. 1. What is that ratio of daises to all flowers in the vase. 2. W

natima [27]

1. 8:15
2. 7:8
Hope this helps!

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3 years ago

Completely simplify the rational expression LaTeX: \frac{7x}{3y} + \frac{12x}{9y}

irina [24]

Answer:

$\frac{11x}{3y}$

Step-by-step explanation:

$\frac{7x}{3y} + \frac{12x}{9y}$

To add the two fractions, you need a common denominator. In this case, the lowest common denominator (LCD) is 9y. That's because 9y is divisible by both 3y and 9y.

The first fraction must be changed so that its denominator is 9y. Do this by multiplying both numerator and denominator by 3.

$\frac{7x}{3y}\cdot\frac{3}{3}+\frac{21x}{9y}=\frac{21x}{9y}+\frac{12x}{9y}\\=\frac{21x+12x}{9y}\\=\frac{33x}{9y}$

Finally, this answer can be simplified ("reduced") by dividing both numerator and denominator by 3, their greatest common factor.

3 0

3 years ago

the graph of F(x), shown below, has the same shape as the graph of G(x)=x^2. but it is shifted up 4 units and to the right 2 uni

ale4655 [162]

Answer:

Step-by-step explanation:

The graph of $y=x^2$ in vertex form is $y=(x-h)^2+k$ where h and k, the vertex, is (0, 0). If we shift the parabola right or left, or up or down, the h and k values take on that reflection. If we move up 4, k goes from a value of 0 to a value of 4; if we move right 2 units, h goes from a value of 0 to a value of 2. Putting that together in work (aka vertex) form: