Answer: The covalent bonds within a molecule are very (strong). However it requires (less) energy to melt a molecular compound than an ionic compound.
This is because the attractive forces between individual molecules are (weaker) than the forces between ions in an ionic compound.
List of the metals that form only one type of ion (that is, metals whose charge is invariant from one compound to another) is below,
Here , we have to list the metals that form only one type of ion (that is, metals whose charge is invariant from one compound to another) and have to identify the group numbers of these metals.
- Hydrogen H+
- Lithium Li+
- Sodium Na+
- Potassium K+
- Rubidium Rb+
- Cesium Cs+
- Beryllium Be2+
- Magnesium Mg2+
- Calcium Ca2+
- Strontium Sr2+
- Barium Ba2+
- Aluminum Al3+
- Zinc Zn2+
- Scandium Sc3+
- Silver Ag+
Co is stable in both +2 and +3 oxidation state. So it can variable. Li only have +1 charge. So it is invariable from one compound to other.
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Answer: The IUPAC name of compound is
6-Ethyl-2-Octene.
Explanation:First of all draw a straight chain of 8 carbon atoms.
Make a double bond between carbon number 6 and 7 numbering from left.
Add ethyl group at position 3 starting from left.
The structure sketched is attached below,
According to rules the longest chain containing a double bond is selected. Numbering is started from the end to which double bond is nearer. So, in our case the double bond starts at carbon 2, hence parent name of compound is 2-Octene. Then the substituent at position 6 is named.
Answer: 60.7 g of
will be formed.
Explanation:
To calculate the moles :
The balanced chemical reaction is
is the limiting reagent as it limits the formation of product and
is the excess reagent.
According to stoichiometry :
6 moles of
produce = 4 moles of
Thus 2.68 moles of
will produce=
of
Mass of
Thus 60.7 g of
will be formed by reactiong 60 L of hydrogen gas with an excess of 