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Misha Larkins [42]
3 years ago
12

A 0.40 kg block can slide up and down a rough a 10-m-high, 30-m-long slope. At the bottom, a stiff spring with spring constant 8

00 N/m is compressed 0.50 m and used to launch the block up the slope. The friction force on the block from the slope is 1.2 N. What is the speed of the block when it reaches the top of the slope, in m/s
Physics
1 answer:
Paul [167]3 years ago
8 0

Answer:

v=11.135m/s

Explanation:

From the question we are told that

Mass m=0.40kg

Frictional friction f=1.2

Spring constant k=800N/m

Compressed x=0.50

Generally the energy balance equation is mathematically given as

1/2kx^2=f*30+m*g*sin \theta*30+1/2m*v^2

if (sin=10/30-1/3)

1/2(800)(0.5)^2=(1.2)*30+(0.4)*9.8*1/3*30+1/2(0.4)*v^2

100=36+39.2+0.20v^2

v^2=\frac{24.8}{0.20}

v=\sqrt{124}

v=11.135m/s

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Answer:

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