Answer:
the tent can hold 8.66 lb of water (or 240 in³ of it)
Step-by-step explanation:
assuming that the tent base is a rectangular area , and the vertical cross section is triangular , then the volume of the tent will be:
Volume of the tent = Area* height/2 = 60 in² * 8 in / 2 = 240 in³
assuming the density of water as 62.4 lb/ft³ then
mass of water = density * volume = 62.4 lb/ft³ * 240 in³ * (1 ft / 12 in)³ = 8.66 lb
then the tent can hold 8.66 lb of water (or 240 in³ of it)
