Answer:
x = 2
y = 5
Step-by-step explanation:
3x + y = 11 equation (1)
-x + y = 3 multiply this equation by -1
x - y = -3 equation (2)
by adding 2 equations
4x = 8
x = 2
by sub. in Equation (2)
2 - y = -3
y = 2+3
y = 5
T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120
Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10
Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)
0 = 3t - 2
2 = 3t
2/3 = t
Plug 2/3 into original equation, this is a maximum. We want the minimum:
0 = t - 5
5 = t
Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5
Area of first rectangle= 5×2=10units
Area of second rectangle= 3×2= 6 units
Area of third rectangle = 5×2= 10 units
Now,
Total area of figure = 10+6+10= <u>26units✓</u>
- 4 w - 4 = - 24
- 4w = - 20
w = 5