Answer:

Step-by-step explanation:
There are exponent rules I posted above that are being used here.
We have (3^-6)^-5
Since we have a power times a power, we multiply 6 and 5 to get -30. Look at the first example in the photo.
So, we're left with 3^-30.
If you look at the photo, there's a rule for negative exponents.
Take the inverse of the base number, so 3 in this case:
1 / 3
and then make the exponent positive after taking the inverse.
So, we should get 1 / 3^30
Hope this helps!
Answer:

Step-by-step explanation:
Hi there! I'm glad I was able to help you solve this equation!
Let's start by simplifying both sides of the equation. It's easier to solve it this way!

Distribute:


Combine 'like' terms:


Next, you'll want to add 36 to both sides of the equation.


Finally, divide both sides by
.


I hope this helped you! Leave a comment below if you have any further questions! :)
Associative property and distributive property
The question is incomplete. Here is the complete question:
A machine covers 5/8 square foot in 1/4 hour. what is the unit rate?
Answer:
2.5 square feet per hour
Step-by-step explanation:
Given:
Area covered by a machine = 
Time taken to cover the given area = 
Now, unit rate of the first quantity with respect to second quantity is the magnitude of the first quantity being when the second quantity is one unit.
Here, the first quantity is the area covered and the second quantity is the time taken.
So, unit rate is the area covered by the machine in 1 hour.
In order to find that, we use the unitary method and divide the area by the total time taken. Therefore,

Thus, the unit rate is 2.5 square feet per hour.
Given that a room is shaped like a golden rectangle, and the length is 29 ft with the ratio of golden rectangle being (1+√5):2, thus the width of the room will be:
ratio of golden triangle=(length if the room)/(width of the room)
let the width be x
thus plugging the values in the expression we get:
29/x=(1+√5)/2
solving for x we get:
x/29=2/(1+√5)
thus
x=(29×2)/(1+√5)
answer is:
x=58/(1+√5)
or
byrationalizing the denominator by multiplying both the numerator and the denominator by (1-√5)
58/(1+√5)×(1-√5)/(1-√5)
=[58(1-√5)]/1-5
=(58√5-58)/4