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3 years ago

Which of the following is an organic acid? CH3COOH C2H6O CH2O CH4

Chemistry

2 answers:

aliya0001 [1]3 years ago

8 0

Answer : The correct option is, $CH_3COOH$

Explanation :

Organic acid : It is an organic compound that has acidic properties.

The common organic acid is the carboxylic acid. The acidity of carboxylic acid is associated with their carboxyl group (-COOH).

(a) $CH_3COOH$ :

It belongs to carboxylic acid functional group in which the the $-COOH$ group is directly attached to the $CH_3$ alkyl group.

(b) $CH_2O\text{ or }HCHO$ :

It belongs to an aldehyde functional group in which the the $-CHO$ group is directly attached to the hydrogen.

(c) $C_2H_6O\text{ or }C_2H_5OH$ :

It belongs to an alcoholic functional group in which the the $-OH$ group is directly attached to the $C_2H_5$ alkyl group.

(d) $CH_4$ : It is a methane molecule.

Hence, an organic acid is $CH_3COOH$

tatyana61 [14]3 years ago

6 0

C) CH20

Hope this helped

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Nitrogen is an essential part of proteins and nucleic acids (DNA).

<h3>Why is nitrogen important?</h3>

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<h3>What happens if nitrogen cycle is disrupted?</h3>

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2 years ago

Green plants use light from the Sun to drive photosynthesis, a chemical reaction in which liquid water and carbon dioxide gas fo

Luda [366]

Answer:

0.800 mol of O2

Explanation:

<em>Calculate the moles of oxygen produced by the reaction of 0.800mol of carbon dioxide.</em>

The balanced equation for the reaction is given as;

6CO2 + 6H2O → C6H12O6 + 6O2

From the reaction;

6 mol of CO2 produces 6 mol of O2

0.0800 mol of CO2 would produce x mol of O2

6 = 6

0.0800 = x

Solving for x;

x = 6 * 0.800 / 6

x = 0.800 mol

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2 years ago

A state function represent?

jeyben [28]

Answer:

a property whose value does not depend on the path taken to reach that specific value.

Explanation:

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3 years ago

The vapor pressure of benzene at 298 K is 94.4 mm of Hg. The standard molar Gibbs free energy of formation of liquid benzene at

horsena [70]

Answer:

ΔfG°(C₆H₆(g)) = 129.7kJ/mol

Explanation:

Bringing out the parameters mentioned in the question;

Vapor pressure = 94.4 mm of Hg

The vaporization reaction is given as;

C₆H₆(l) ⇄ C₆H₆(g)

Equilibrium in terms of activities is given by:

K = a(C₆H₆(g)) / a(C₆H₆(l))

Activity of pure substances is one:

a(C₆H₆(l)) = 1

Assuming ideal gas phase activity equals partial pressure divided by total pressure. At standard conditions

K = p(C₆H₆(g)) / p°

Where p° = 1atm = 760mmHg standard pressure

We now have;

K = 94mmHg / 760mmHg = 0.12421

Gibbs free energy is given as;

ΔG = - R·T·ln(K)

where R = gas constant = 8.314472J/molK

So ΔG° of vaporization of benzene is:

ΔvG° = - 8.314472 · 298.15 · ln(0.12421)

ΔvG° = 5171J/mol = 5.2kJ/mol

Gibbs free energy change of reaction = Gibbs free energy of formation of products - Gibbs free energy of formation of reactants:

ΔvG° = ΔfG°(C₆H₆(g)) - ΔfG°(C₆H₆(l))

Hence:

ΔfG°(C₆H₆(g)) = ΔvG°+ ΔfG°(C₆H₆(l))

ΔfG°(C₆H₆(g)) = 5.2kJ/mol + 124.5kJ/mol

ΔfG°(C₆H₆(g)) = 129.7kJ/mol

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3 years ago

Hurry PLEASE HELP!

avanturin [10]

B. 11,540

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.

Usually radioactive elements have an unstable atomic nucleus.

General formulas used in decay:

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}$

T = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

Nt=25 g

No=100 g

t1/2=5770 years

$\tt 25=100\dfrac{1}{2}^{T/5770}\\\\\dfrac{1}{4}=\dfrac{1}{2}^{T/5770}\\\\2=T/5770\rightarrowT=11540~years$

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3 years ago