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3 years ago

Which of the following is an organic acid? CH3COOH C2H6O CH2O CH4

Chemistry

2 answers:

aliya0001 [1]3 years ago

8 0

Answer : The correct option is, $CH_3COOH$

Explanation :

Organic acid : It is an organic compound that has acidic properties.

The common organic acid is the carboxylic acid. The acidity of carboxylic acid is associated with their carboxyl group (-COOH).

(a) $CH_3COOH$ :

It belongs to carboxylic acid functional group in which the the $-COOH$ group is directly attached to the $CH_3$ alkyl group.

(b) $CH_2O\text{ or }HCHO$ :

It belongs to an aldehyde functional group in which the the $-CHO$ group is directly attached to the hydrogen.

(c) $C_2H_6O\text{ or }C_2H_5OH$ :

It belongs to an alcoholic functional group in which the the $-OH$ group is directly attached to the $C_2H_5$ alkyl group.

(d) $CH_4$ : It is a methane molecule.

Hence, an organic acid is $CH_3COOH$

tatyana61 [14]3 years ago

6 0

C) CH20

Hope this helped

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How many grams of barium sulfate form when 35.0 ml of 0.160 m barium chloride reacts with 58.0 ml of 0.065 m sodium sulfate? do

vazorg [7]

Barium sulfate weighs 0.88 grams per gram.

Mass:

A physical body's overall composition is measured by its mass.

Inertia, or the body's resistance to acceleration in the presence of a net force, is also measured by it.

The mass of a thing also affects how strongly it attracts other bodies through gravity.

In the SI, the kilogram serves as the basic mass unit (kg).

This information

Moles of BaCl2 equal 5.6 x 103 (35 x 0.160 / 1000)

sodium sulfate moles equal 58 x 0.065, or 3.77 x 103,

Na2SO4 with BaCl2 ——————————-> 2NaCl plus BaSO4

Na2SO4 is the limiting agent here.

Therefore, the product relies on limiting reagent.

1 mol of Na2SO4 produces 1 mol of BaSO4.

0.00377 moles of BaSO4 is one mole.

moles = mass / molar mass of BaSO4.

0.00377 = mass / 233.4

BaSO4 mass is 0.88 g.

So, 0.88 grams of barium sulfate make up one gram.

To know more about the mass visit:

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1 year ago

Which statements correctly describe the rock cycle? Check all that apply.

pickupchik [31]

Answer: I italicize for checking

Rocks are preserved through the process.
Rocks change from one type to another.
Different rock groups are interrelated.
Rocks change from one type to another in a specific order.
Environmental conditions influence a change in rock type.

Explanation:

Rocks are preserved, as in you can't destroy them completely, but no, they don't stay the same they change.

3 0

2 years ago

Calculate the molarity of a solution consisting of 25.0 g of KOH in 3.00 L of solution.

melomori [17]

Answer:

0.15M

Explanation:

The equation for molarity is M= n/L. Where "M" is Molarity, "n" is the number of moles of solute, and "L" is the total liters in solution.

You need to calculate the number of moles from the given grams. The molar mass of KOH is (39.098+ 16 +1.008)= 56.106g. To calculate the mols of KOH, $\frac{25.0g}{1}$ × $\frac{1 mol}{56.106g}$ = 0.44558... mol, you see that the grams unit cancel out leaving you with mol as the unit.

The volume is given in L already so no need to do any conversion. M= $\frac{0.4558mol}{3.00L}$ = 0.1485M ≈ 0.15M

5 0

2 years ago

D. What do all of the molecules in the table have in common?

blsea [12.9K]

Answer:

They all have a certain amount of protons electrons and neutrons.

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3 years ago

4.50 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 1

Anna11 [10]

Answer:

$\mathbf{C_{10}H_8}$ ( Naphthalene )

Explanation:

Given that:

4.50 g of a Compound X is made up of Carbon , Hydron and Oxygen

It's molecular molar mass = 128 g/mol

Compound X undergoes combustion reaction and the product yield :

CO_2 with mass 15.47g and :

H_2O with mass 2.53 g

The objective is to use this information to determine the molecular formula of X.

We all know that ; number of moles = mass/molar mass

where the molar mass of H_2O is 18 g/mol

number of moles of H_2O product = 2.53 g/18 g/mol

number of moles of H_2O product = 0.1406 moles

Also; the molar mass of CO_2 product = 44 g/mol

number of moles of CO_2 product = 15.47g/ 44 g/mol

number of moles of CO_2 product = 0.3516 moles

number of moles of Compound X in the reactant side= 4.50 g /128 g/mol

number of moles of Compound X n the reactant side= 0.03516 moles

Now; number number of moles of CO_2 in reactant = 0.3516 moles/0.03516 moles

Now; number number of moles of CO_2 in reactant = 10

number of moles of H_2O reactant = 0.1406 moles × 2/0.03516

number of moles of H_2O reactant = 7.997 ≅ 8

Since we said the Compound X is known to be made of Carbon C , Hydrogen H and Oxygen O

Then the molecular formula can be written as :

$\mathbf{C_{10}H_8O_{x}}$

In order to find the x; we have

128 = (12 × 10 + 1 × 8 + 16 × x)

128 = 120 + 8 + 16x)

128 = 128 + 16 x

128 - 128 = 16 x

0 = 16 x

x = 0/16

x = 0

As x = 0 ; hence there are no oxygen present in the reaction

Thus; the molecular formula of Compound X = $\mathbf{C_{10}H_8}$ which is also known as Naphthalene

5 0

3 years ago