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kobusy [5.1K]
3 years ago
5

How do functional groups affect the chemical properties of a molecule?

Chemistry
1 answer:
Setler [38]3 years ago
8 0
In organic chemistry, functional groups are specific groups of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules. The same functional group will undergo the same or similar chemical reactions regardless of the size of the molecule it is a part of. 
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How many kilograms of oil are needed to heat 190 kg of water from 22 ∘C to 100∘C? (Assume that 1lb=454g, the specific heat of li
Digiron [165]

Answer:

m = 1.3 Kg

Explanation:

according  to Specific Heat Formula :

Q = mc∆T

when Q is the heat energy in Joules

m is the mass of water

C is the specific heat its unit J/kg∙K

∆T change in temperature (the final t - the initial t)

by substitution:

Q = 190000 g * 4.184 J/g∘C *78

Q = 62006880 J

when The combustion of 1.0 lb of oil provides 2.2×107J

So lb of oil when Q = 62006880 J = 2.8 Ib

and when 1lb=454g

So 2.8 Ib = 1271.2 g = 1.3 Kg

8 0
3 years ago
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masha68 [24]

1e

2

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7 0
3 years ago
URGENT! A solution that contains less solute than it can possibly hold at a given temperature.
Zigmanuir [339]

Answer:

Diluted solution

Explanation:

It is simple in terms of looking in to it, solute is the solid part of the solution and if a small quantity is dissolved in a solvent which can hold more then the solute added will make the solution diluted and for more info- other answers depict that there is more solute in the solution therefore others can not be the answer

4 0
3 years ago
What is the isotopic notation for Carbon-14.
Zarrin [17]

Answer:

https://socratic.org/questions/what-is-the-isotope-notation-for-carbon-14

Explanation:

8 0
3 years ago
Read 2 more answers
Phosgene has the elemental compositions of 12.14% carbon, 16.17 % oxygen, and 71.69% chlorine by mass.
inessss [21]

Answer:

a) COCl₂.

b) The molecular formula is COCl₂.

Explanation:

To obtain empirical formula of phosgene you should divide elemental compositions over atomic mass of each atom, and divide these results between the smallest, thus:

C = 12,14%/12,01 = 1,01

O = 16,17%/16 = 1,01

Cl = 71,69%/35,45 = 2,02

Empirical formula:

C = 1,01/1,01 = 1

O = 1,01/1,01 = 1

Cl = 2,02/1,01 = 2

C₁O₁Cl₂ ≡ COCl₂

b) You need to find the molar mass of the empirical formula to determine the ratio of the real formula, thus:

1×C 12,01g/mol =

1×O 16 g/mol =

2×Cl 35,35g/mol = 98,91g/mol

As real molecular mass is 98,9 g/mol. The molecular formula: COCl₂

I hope it helps!

6 0
4 years ago
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