Answer:
(K) = [H2] [Cl2] / [HCl]²
Explanation:
The equation of the reaction is given as;
2 HCl (g) ⇔ H2 (g) + Cl2 (g)
The Equilibrium constant is the ratio of the concentration of the products and reactants raised to the power of their coefficients
Products = H2 and Cl2
Reactants = HCl
Equilibrium constant (K) = [H2] [Cl2] / [HCl]²
Answer:
Explanation:
MM: 2.016 17.03
N₂ + 3H₂ ⟶ 2NH3
m/g: 26.3
1. Theoretical yield
(a) Moles of H₂
(b) Moles of NH₃
(c) Theoretical yield of NH₃
(d) Percent yield
Answer: Your balanced equation is 2Al + 3S --> Al_2S_3. In two separate equations, first use the 48.5g of Al to find the amount (in moles) of Al_2S_3. Then use the 62.8g of S to find the amount (in moles) of Al_2S_3. By doing these, you find which reactant (the Al or the S) produces the least amount of Al_2S_3. Since it's the S, that's the limiting reactant: you then use that 62.8g of S to find how many grams of Al will be used in the reaction. (Use the same balanced equation.) You find that 35.2g of Al will be used, then find the excess by subtracting that 35.19 from the original 48.5g. Your excess amount is 13.3g of Al!
Explanation:
hopefully this is what you were looking for <3 :)