Ammonia NH3, can be synthesized by the following reaction: 2NO + 5H2 → 2NH3 +2 H2O If you start with 90.0 grams of NO and an unl
1 answer:
3 moles of water i.e. 54 gram of water is produced by starting the reaction with 99 grams of NO
Explanation:
The reaction to produce ammonia is shown below:
2NO + 5H2 → 2NH3 +2 H2O
From the reaction it is seen that NO is the limiting reagent in the reaction.
Atomic weight of NO=30.01 g/mol
the weight of NO in reaction is given 90 grams
Number of moles= 90÷30.01
= 2.99 or 3 moles of NO
It can be seen that 3 moles of NO is taking part in the reaction.
From the chemical equation it is seen that 2 moles of NO will yield 2 moles of water and 2 moles of ammonia.
From the stoichiometry:
2 moles of NO will yield 2 moles of O
3 moles of NO will yield x moles of O
x= 3 moles
The weight of water produced can be obtained by the formula
Number of moles= weight ÷atomic weight
weight= 18×3
= 54 grams
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