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3 years ago

Given 2 points how would you write an algebraic representation

Mathematics

1 answer:

Ganezh [65]3 years ago

7 0

Answer:

Find the Equation of a Line Given That You Know Two Points it Passes Through. The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept.

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Select the correct answer.

kramer

Answer:

xxx

Step-by-step explanation:

5 0

2 years ago

Kamil invests 9000 for 4 years his investment pays compound interest of x% per anumn

elena-s [515]

To get the Total amount upon investment for the compound interest, plug in the value of x into the given expression bellow

A = 9,000.00(1 + x/100)^(4)

Given data

Principal = $9000

Time = 4 years

Rate = x% per annum

<h3>Solution</h3>

Step one:

First, convert R as a percent to r as a decimal

r = x/100

Step two:

Then solve the equation for A

A = P(1 + x/100)^t

A = 9,000.00(1 + x/100)^(4)

Summary:

The total amount accrued, principal plus interest, with compound interest on a principal of $9,000.00 at a rate of x% per year.

Learn more about compound interest here:

brainly.com/question/24924853

6 0

2 years ago

Which expression is equivalent to 250 + 150 ?

salantis [7]

Answer:

if 25c + 15d = 0, then d = -25/15c

Step-by-step explan

just yes, that

3 0

3 years ago

Read 2 more answers

PLEASE HELP NEED TO KNOW IF IM CORRECT WILL REWARD BRAINLIEST ANSWER!

Neporo4naja [7]

X^2=256

x=±√256

x=±16

x=-16 and 16

8 0

3 years ago

An certain brand of upright freezer is available in three different rated capacities: 16 ft3, 18 ft3, and 20 ft3. Let X = the ra

ruslelena [56]

Answer:

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

$E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6=349.2$

$V(X) = E(X^2)-[E(X)]^2=349.2-(18.6)^2=3.24$

The expected price paid by the next customer to buy a freezer is $466

Step-by-step explanation:

From the information given we know the probability mass function (pmf) of random variable X.

$\left|\begin{array}{c|ccc}x&16&18&20\\p(x)&0.3&0.1&0.6\end{array}\right|$

Point a:

The Expected value or the mean value of X with set of possible values D, denoted by E(X) or μ is

$E(X) = $\sum_{x\in D} x\cdot p(x)$

Therefore

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

If the random variable X has a set of possible values D and a probability mass function, then the expected value of any function h(X), denoted by E[h(X)] is computed by

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)$

So $h(X) = X^2$ and

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)\\E[X^2]=$\sum_{D}x^2\cdot p(x)\\ E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6\\E(X^2)=349.2$

The variance of X, denoted by V(X), is

$V(X) = $\sum_{D}E[(X-\mu)^2]=E(X^2)-[E(X)]^2$

Therefore

$V(X) = E(X^2)-[E(X)]^2\\V(X)=349.2-(18.6)^2\\V(X)=3.24$

Point b:

We know that the price of a freezer having capacity X is 60X − 650, to find the expected price paid by the next customer to buy a freezer you need to:

From the rules of expected value this proposition is true:

$E(aX+b)=a\cdot E(x)+b$

We have a = 60, b = -650, and E(X) = 18.6. Therefore

The expected price paid by the next customer is

$60\cdot E(X)-650=60\cdot 18.6-650=466$

4 0

3 years ago