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9966 [12]
3 years ago
8

Answer fast helpp.........................

Mathematics
1 answer:
Akimi4 [234]3 years ago
7 0

Answer:

20°

Step-by-step explanation:

In circle with center O, PS is diameter.

m\angle PRS =90\degree

(angle inscribed in semicircle)

PQRS is a cyclic quadrilateral.

Opposite angles of a cyclic quadrilateral are supplementary.

\therefore m\angle QPS + m\angle QRS = 180\degree

\therefore (x\degree +25\degree) +(45\degree +90\degree) = 180\degree

\therefore x\degree +25\degree + 45\degree +90\degree = 180\degree

\therefore x\degree +160\degree = 180\degree

\therefore x\degree = 180\degree-160\degree

\huge\red {\therefore x\degree = 20\degree}

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A car brought for 13000 deprecitates at 15 percent per year find value of car after 5 years
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the value of the car will be 3250 after 5 years

Step-by-step explanation:

the value of the car = 13000

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time = 5 years

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=\frac{13000 X 15 X 5}{100}

= 9750

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4 0
4 years ago
John is selling sets of Legos and makes a 10% commission on all sales. what would his
kodGreya [7K]

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3 0
3 years ago
Solve the equation. 8 – 2x = –8x + 14
goldenfox [79]

Answer:

x=1

Step-by-step explanation:

We are asked to solve the given equation: 8-2x=-8x+14.

To solve this equation we will combine like terms by moving all the terms containing x to the left hand side of equation and terms without x to right hand side of equation.

Let us add 8x to both sides of our equation.

8-2x+8x=-8x+8x+14

8-2x+8x=14

8+6x=14

Let us subtract 8 from both sides of our equation.

8-8+6x=14-8

6x=14-8

6x=6

Upon dividing both sides of our equation by 6 we will get,

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x=\frac{6}{6}

x=1

Therefore, the value of x equals 1 will satisfy our given equation.

8 0
3 years ago
Read 2 more answers
One runner passes another runner traveling in the same direction on a hiking trail. the faster runner is jogging 4 miles per hou
Rus_ich [418]

Both runners are running at a constant speed. Say that the fastest runner goes at speed v_f (for fast) and the slowest goes at speed v_s (for slow).

Let's start the observation at the moment of the passing: the two runners are in the exact same position. The laws that determine their position in the future are

\text{fast runner: } s_f = v_ft,\quad \text{slow runner: } s_s = v_st

This means that the difference between the two positions is given by

s_f-s_s = v_ft-v_st = (v_f-v_s)t

Now we plug in the fact that the faster speed is four more than the slower speed, i.e. v_f = v_s+4. The equation for the difference becomes

s_f-s_s = (v_f-v_s)t = (v_s+4-v_s)t = 4t

And we want this difference to be 5/8 miles, so the request is

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To solve for t, divide both sides by 4 to get

\cfrac{5}{32} = t

So, after 5/32 of a hour the two runners will be at 5/8 miles from each other.

4 0
4 years ago
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