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strojnjashka [21]
2 years ago
13

What is the derivative of Y =x√(2x + 1)/e^xsin^3(x).?

Mathematics
1 answer:
blagie [28]2 years ago
3 0
-\dfrac{\mathrm{e}^{-x}\left(\left(2x^2-2x-1\right)\sin\left(x\right)+\left(6x^2+3x\right)\cos\left(x\right)\right)}{\sqrt{2x+1}\sin^4\left(x\right)}.
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HELP Me NOW NOW NOW NOW
german

Answer:

The answer is 9/16.

Step-by-step explanation:

Using Indices Law,

{( \frac{a}{b}) }^{n} ⇒ \frac{ {a}^{n} }{ {b}^{n} }

So for this question :

{ (\frac{3}{4}) }^{2}

=  \frac{ {3}^{2} }{ {4}^{2} }

=  \frac{3 \times 3}{4 \times 4}

=  \frac{9}{16}

7 0
3 years ago
the granola summer buys used to cost six dollars per pound but it has been marked up 15% a how much did it cost summer to buy 2.
EastWind [94]
17.94
Because 15% of $6 is .9 so 
2.6x6.9=17.94
5 0
2 years ago
If the number of hours you hours you work is proportional to the amount of money you earn per hour, which og tye following state
Basile [38]

Answer:

it should be a

Step-by-step explanation:

if you work for $10 an hour, and work for 2 hours, you make $20 but if you double the hours worked, so 4 hours, you make $40, which is double the hours, and double the money

3 0
2 years ago
Please answer this I will give u​
satela [25.4K]

Answer:

Step-by-step explanation:

The 3 angles must add up to 180. So

6x + 4x + 2x = 180

12x = 180

x = 15

Plug this into all the angles and you have your answers

5 0
3 years ago
Read 2 more answers
A car rental company charges a one-time application fee of 40 dollars, 55 dollars per day, and 13 cents per mile for its cars. A
liberstina [14]

Answer:

A) C(d,m) = 40 + 55d + 0.13m

B) $448

Step-by-step explanation:

Let 'd' be the number of days and 'm' the number of miles driven.

A) The cost function that describes a fixed amount of $40, added to a variable amount of $55 per day (55d) and a variable amount of 13 cents per mile (0.13m) is:

C(d,m) = 40 +55d +0.13m

B) If  d = 5 and m =600, the total cost is:

C(5,600) = 40 +55*6 +0.13*600\\C(5,600)=\$448

The cost is $448.

3 0
3 years ago
Read 2 more answers
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