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strojnjashka [21]
3 years ago
13

What is the derivative of Y =x√(2x + 1)/e^xsin^3(x).?

Mathematics
1 answer:
blagie [28]3 years ago
3 0
-\dfrac{\mathrm{e}^{-x}\left(\left(2x^2-2x-1\right)\sin\left(x\right)+\left(6x^2+3x\right)\cos\left(x\right)\right)}{\sqrt{2x+1}\sin^4\left(x\right)}.
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Name the smallest even number divisible by 6 and 9.
Step2247 [10]

Answer:

18

Step-by-step explanation:

5 0
2 years ago
What is the scale factor of the dilation shown? Quadrilateral D E F G has side lengths 4, 10, 8, and 4. Quadrilateral D prime E
ira [324]

Answer:

i think the scale factor is 3:2

Step-by-step explanation:

To figure the total difference divide:

6 divided by 4 = 1.5

1.5 = 3/2

pls tell me if wrong

Hope this helps

8 0
3 years ago
$10000 in an account paying 8% compounded annually. how much will the account be worth in 18 years
lawyer [7]
10000x8%= $800 anually
anually=yearly
800x18=14400

5 0
3 years ago
what is the domain of the function: {(1, 3); (3, 5); (5, 7); (7, 9)}? a. {1, 3, 5, 7, 9} b. {1, 3, 5, 7} c. {1, 9} d. {3, 5, 7,
Papessa [141]
B. 1, 3, 5, and 7 are x values. Domain is the x value.
6 0
3 years ago
Denise and Jacqueline are training for a swimming and running race.
bezimeni [28]

Answer:

Jacqueline runs at 6.25 minutes per mile

Step-by-step explanation:

Here we have that the total training time for Jacqueline = 54 minutes

The time for which Jacqueline swims = 30 minutes

Therefore, the time in which Jacqueline runs = 54 min. - 30 min. = 20 minutes

Therefore the equation for Jacqueline's speed = Distance/Time we have

Jacqueline's pace = 3.2 miles/20 minutes = 0.16 miles/minute

Therefore Jacqueline's pace = 0.16 miles/minute

The equation for Jacqueline's pace in miles/minute is presented as follows

Jacqueline's pace in miles/minute = Time of running/Distance

Jacqueline's pace in miles/minute  = 1/0.16 miles/minute = 6.25 minutes/mile.

5 0
3 years ago
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