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lorasvet [3.4K]
3 years ago
7

What is 231.5 in a percentage?

Mathematics
2 answers:
rosijanka [135]3 years ago
8 0

Answer:

57.8

Step-by-step explanation:

makvit [3.9K]3 years ago
4 0

Answer:

23 150%

Step-by-step explanation:

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Before a new video game is released, it is tested by a number of volunteer gamers. During testing, the experimental probability
sergejj [24]
So to get 500 to 1,000,000 you need to multiply it 2,000 times. With that you also need to multiply the 1 2,000 times so 2,000 players will get a perfect score.
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3 years ago
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+) Evaluate the expression 81 – 82.<br> 81 – 82 =
Temka [501]
81 - 8^2 is 17 ..............
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3 years ago
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How to solve a one step equation of R+3= -6 1/2 <br> please show all the work
IgorC [24]
Solve for R:
R + 3 = -(1/2 + 6)
Put 1/2 + 6 over the common denominator 2. 1/2 + 6 = (2×6)/2 + 1/2:
R + 3 = -(2×6)/2 + 1/2
2×6 = 12:
R + 3 = -(12/2 + 1/2)
12/2 + 1/2 = (12 + 1)/2:
R + 3 = -(12 + 1)/2
12 + 1 = 13:
R + 3 = -13/2
Subtract 3 from both sides:
R + (3 - 3) = -13/2 - 3
3 - 3 = 0:
R = -13/2 - 3
Put -13/2 - 3 over the common denominator 2. -13/2 - 3 = (-13)/2 + (2 (-3))/2:
R = (-13)/2 - (3×2)/2
2 (-3) = -6:
R = (-6)/2 - 13/2
(-13)/2 - 6/2 = (-13 - 6)/2:
R = (-13 - 6)/2
-13 - 6 = -19:
Answer:  R = (-19)/2
6 0
3 years ago
Terri played 70 tournament chess games during the school year and won 49 of them. What is her win-to-loss ratio?
Scilla [17]

Alright so the answer would be letter B, because

win-to-loss

49 to 21 (You can determine her losses by subtracted the number of wins from her total number of games played)

Now you must simplify your answer

7 is the greatest common factor (GCF) of both 49 and 21

Now divide both 49 and 21 by 7 to get

7 to 3

7 0
3 years ago
Estimate the perimeter and the area of the shaded figure to the nearest whole number.
soldier1979 [14.2K]

Answer:

Step-by-step explanation:

The area and perimeter of the given shaded figure are respectively 33.12 unit² and 20.56 units.

Area and perimeter-based problem:

What information do we have?

Radius of semi-circle = 8 / 2 = 4 unit

Length of remain Rectangle = 8 unit

Width of remain Rectangle = 2 unit

Perimeter of shaded figure = πr + (l + 2b)

Perimeter of shaded figure = (3.14)(4) + [4 + (2)(2)]

Perimeter of shaded figure = 12.56 + 4 + 4

Perimeter of shaded figure = 20.56 units

Area of shaded figure = πr²/2 + lb/2

Area of shaded figure = (3.14)(4)²/2 + (8)(2)/2

Area of shaded figure = (3.14)(8) + 8

Area of shaded figure = 25.12 + 8

Area of shaded figure = 33.12 unit²

5 0
2 years ago
Read 2 more answers
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