The volume in mL of ethanol (C₂H₆O) present in the bottle is 487.5L
HOW TO CALCULATE VOLUME OF ETHANOL:
- According to this question, a particular beer is 65.0% ethanol by volume. This means that the beer contains 65/100 of ethanol.
- If a single bottle of beer contains a total of 750.0 mL of beer, the volume of ethanol in the bottle is calculated as follows:
- Therefore, volume in mL of ethanol (C₂H₆O) present in the bottle is 487.5L
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10 Ne:
1s², 2s², 2p⁶
Answer C
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You would calculate them by dividing them and then multiplying to get the final answer
Answer:
B. They are stereoisomers
C. They are enantiomers
Explanation:
Let us consider all the options
A. D and L-glucose are not necessarily furanose, they can also be in free form (open chain) or as a six-membered ring (pyranose)
B. These sugars are stereoisomers as they have the same molecular formula, same bonds but with the different spacial arrangement.
C. Two structures are called enantiomers, if they are stereoisomers and are mirror images of each other and are not-superimposable. The given pair of structures satisfy these conditions
D. Epimers are diastereoisomers (same molecular formula and connectivity having a different spacial arrangement but are not mirror images and non-superimposable) with only one different stereocenter (if there are more than one). This is not the case
E. All monosaccharides (any sugar that cannot be hydrolysed to a simpler sugar) are reducing sugars. So, this option is invalid
Answer:
It follows a clearly laid out method.
