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serg [7]
3 years ago
11

How would i calculate molecules of water produced in a reaction?

Chemistry
1 answer:
levacccp [35]3 years ago
5 0
You would calculate them by dividing them and then multiplying to get the final answer
You might be interested in
1. How many molecules are in 240g of sulfuric acid?
Soloha48 [4]

Answer:

14.8 × 10²³ molecules

Explanation:

Given data:

Mass of sulfuric acid = 240 g

Number of molecules = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

Number of moles of sulfuric acid

<em>Number of moles = mass/ molar mass</em>

Number of moles =  240 g/ 98 g/mol

Number of moles = 2.45 mol

Number of molecules:

1 mole = 6.022 × 10²³ molecules

2.45 × 6.022 × 10²³ molecules

14.8 × 10²³ molecules

3 0
3 years ago
How many Molecules does CH4 Have
valentinak56 [21]

Answer:

The amount of molecules in CH4, also known about methane is simply 0.85 * 6.02210 * 10^23 This amounts to about 5.1 * 10^23

4 0
3 years ago
All of the following are exothermic reactions except,
monitta
Exothermic reactions release heat the surrounding. So Freezing? 
8 0
2 years ago
Looking at the periodic table, which of these elements has the smallest atomic radius?
Sauron [17]
Helium
Remember: electron filling of atomic shell  ...
 The element which have electron in the lowest quantum shell will have the smallest atomic radius\

He:1s1   (Helium)

H:1s2   (hydrogen)
8 0
2 years ago
2- A sheet of steel 3.0-mm thick has nitrogen atmospheres on both sides at 900°C and is permitted to achieve a steady-state dif
Bezzdna [24]

Answer:

2.78x10⁻³ m

Explanation:

Nitrogen diffusion in the steel can be expressed using the following equation:

J = - D*\frac{\Delta C}{\Delta x} = - D*\frac{C_{1} - C_{2}}{x_{1} - x_{2}}  

<u>Where:</u>                        

J: is the diffusion flux = 1.0x10⁻⁷ kgm⁻²s⁻¹    

D: is the diffusion coefficient = 1.85x10⁻¹⁰ m²/s  

C₁: is the concentration of nitrogen in the steel at the surface = 2 kg/m³

C₂: is the concentration of nitrogen at the distance x₂ = 0.5 kg/m³

x₁: is the distance at the surface = 0

x₂: is the distance to find    

Hence, we have:

J = - D*\frac{C_{1} - C_{2}}{- x_{2}}    (1)

Solving equation (1) for x₂:

x_{2} = D \frac{C_{1} - C_{2}}{J} = 1.85 \cdot 10^{-10} m^{2}/s \frac{2 kg/m^{3} - 0.5 kg/m^{3}}{1.0 \cdot 10^{-7} kgm^{-2}s^{-1}} = 2.78 \cdot 10^{-3} m                                        

Therefore, the nitrogen will enter 2.78x10⁻³ m into the sheet.

I hope it helps you!

7 0
3 years ago
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