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3 years ago

Why is gold considered matter?

Chemistry

1 answer:

Yakvenalex [24]3 years ago

3 0

Answer:

All matter is made up of substances called elements, which have specific chemical and physical properties and can't be broken down into other substances through ordinary chemical reactions. Gold, in this case, is an element so, therefore, it is considered matter.

Hope it helped :)

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You performed an experiment to find out how far three different sizes of

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B how much farther does the arrow fly when you use a stronger bow

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3 years ago

Draw two lewis structures for a compound with the formula c4h10. No atom bears a charge, and all carbon atoms have complete octe

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Answer:

See pictures!

Explanation:

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2 years ago

A mixture containing nitrogen, hydrogen, and iodine established the following equilibrium at 400 °C:2NH3(g) + 3I2(g) ⇌ N2(g) + 6

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Explanation:

The given equation is as follows.

$2NH_{3}(g) + 3I_{2}(g) \rightleftharpoons N_{2}(g) + 6HI(g)$

$N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2NH_{3}(g); K_{c_{1}} = 0.50$ ... (1)

$H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g); K_{c_{2}} = 50$ ... (2)

To balance the atoms, multiply equation (2) by 3. Hence, the equation (2) can be re-written as follows.

$3H_{2}(g) + 3I_{2}(g) \rightleftharpoons 6HI(g); K_{c_{2}} = (50)^{3}$ ... (3)

Now, subtract equation (1) from equation (3). So, the equation formed will be as follows.

$3I_{2} - N_{2} \rightleftharpoons 6HI - 2NH_{3}$

This equation can also be re-written as follows.

$3I_{2} + 2NH_{3} \rightleftharpoons N_{2} + 6HI$

This equation is similar to the equilibrium equation given to us.

Therefore, during this subtraction the equation constants get divided as follows.

$K^{'}_{c} = \frac{K_{c_{2}}}{K_{c_{1}}}\\= \frac{(50)^{3}}{0.50}\\= 250000$

Thus, we can conclude that the value of $K_{c}$ for this reaction is 250000.

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2 years ago

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2 years ago

19) What is the molarity of a KOH solution if 200 ml of the solution contains 0.6 moles KOH?

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