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Firdavs [7]
3 years ago
5

In a thundercloud there may be an electric charge of 26 C near the top of the cloud and −26 C near the bottom of the cloud. If t

hese charges are separated by about 7 km, what is the magnitude of the electric force between these two sets of charges? The value of the electric force constant is 8.98755 × 109 N · m2 /C 2
Physics
1 answer:
strojnjashka [21]3 years ago
6 0

Answer:

869,142,857.1 N

Explanation:

use this formula,

F =  \frac{Q1  Q2 }{4\pi eo  R^{2} }

All the value is given.

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A charged particle moves through a velocity selector at a constant speed in a straight line. The electric field of the velocity
WARRIOR [948]

Answer:

The charge-to-mass ratio of the particle is 5.7 × 10⁵ C/kg

Explanation:

From the formulae

F = qvB and F = mv²/r

Where F is Force

q is charge

v is speed

B is magnetic field strength

m is mass

and r is radius

Then,

qvB = mv²/r

qB = mv/r

We can write that

q/m = v/rB ---- (1)

Also

From Electric force formula

F = Eq

Where E is the electric field

and magnetic force formula

F = Bqv

Since, electric force = magnetic force

Then, Eq = Bqv

E = Bv

∴ v = E/B

Substitute v = E/B into equation (1)

q/m = (E/B)/rB

∴ q/m = E/rB²

(NOTE: q/m is the charge to mass ratio)

From the question,

E =  3.10 ×10³ N/C

r = 4.20 cm = 0.0420 m

B = 0.360 T

Hence,

q/m = 3.10 ×10³ / 0.0420 × (0.360)²

q/m = 569517.9306 C/kg

q/m = 5.7 × 10⁵ C/kg

Hence, the charge-to-mass ratio of the particle is 5.7 × 10⁵ C/kg.

7 0
3 years ago
Problem 3) Bob stands at the edge of the swimming pool holding a laser 1.5m above the ground. He shines the red laser beam onto
Vadim26 [7]

Answer:

d = 5.75m

Explanation:

Using snell's law, we have,

n₁ × sin(i) = n₂ × 2 × sin(r)

n1= refractive index of 1st medium= 1

n2=  refractive index of 2nd medium = 1.33

r= angle of reflection

therefore,

r = \sin^{-1}\frac{n_1\sin i}{n_2}

Here,

i = 90 - θ

\theta = \tan^-^1(\frac{1.5}{3} )\\\\=26.56^\circ

r = \sin^{-1}\frac{n_1\sin i}{n_2}

r = \sin^{-1}\frac{(1)\sin (90-26.56)}{1.33}\\\\r = 42.26m

\tan r = \frac{2.5}{d_1}

d_1 = \frac{2.5}{\tan (42.26)} \\\\d_1 = 2.75m

Therefore, the distance is

d = 3 + d₁

d = 3 + 2.75

d = 5.75m

6 0
3 years ago
Which pair of countries are both part of the crib Caribbean cultural regions in North America
Anni [7]
I believe Cuba and the Bahamas.
6 0
3 years ago
Two small objects each with a net charge of +Q exert a force of magnitude F on each other. We replace one of the objects with an
Alona [7]

Answer:

F'= 4F/9

Explanation:

Two small objects each with a net charge of +Q exert a force of magnitude F on each other. If r is the distance between them, then the force is given by :

F=\dfrac{kQ^2}{r^2} ...(1)

Now, if one of the objects with another whose net charge is + 4Q is replaced and also the distance between +Q and +4Q charges is increased 3 times as far apart as they were. New force is given by :

F'=\dfrac{kQ\times 4Q}{(3r)^2}\\\\F'=\dfrac{4kQ^2}{9r^2}.....(2)

Dividing equation (1) and (2), we get :

\dfrac{F}{F'}=\dfrac{\dfrac{kQ^2}{r^2}}{\dfrac{4kQ^2}{9r^2}}\\\\\dfrac{F}{F'}=\dfrac{kQ^2}{r^2}\times \dfrac{9r^2}{4kQ^2}\\\\\dfrac{F}{F'}=\dfrac{9}{4}\\\\F'=\dfrac{4F}{9}

Hence, the correct option is (d) i.e. " 4F/9"

7 0
3 years ago
Sandi believes that people who eat at McDonald's are overweight, so she decides to do a naturalistic observation of people who e
lubasha [3.4K]

Answer:

observer bias

Explanation:

Based on the information provided within the question the thing that should concern us the most about Sandi's observations is Observer Bias. This term refers to the tendency of a researcher to see what they want as opposed to what is actually happening. This can be said because of Sandi's belief that McDonald clients are all overweight, by having this belief before actually having come to this conclusion with a series of tests, it might lead her to believe this to be true regardless of what she observes during the experiment.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

6 0
3 years ago
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