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Firdavs [7]
3 years ago
5

In a thundercloud there may be an electric charge of 26 C near the top of the cloud and −26 C near the bottom of the cloud. If t

hese charges are separated by about 7 km, what is the magnitude of the electric force between these two sets of charges? The value of the electric force constant is 8.98755 × 109 N · m2 /C 2
Physics
1 answer:
strojnjashka [21]3 years ago
6 0

Answer:

869,142,857.1 N

Explanation:

use this formula,

F =  \frac{Q1  Q2 }{4\pi eo  R^{2} }

All the value is given.

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Answer:

The mechanical energy of the ball-Earth-floor system the instant the ball left the floor is 7 Joules.

Explanation:

It is given that,

Initial gravitational potential energy of the ball-Earth-floor system is 10 J.

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Let U is the mechanical energy of the ball-Earth-floor system the instant the ball left the floor. Due to the conservation of energy, the mechanical energy is equal to difference between initial gravitational potential energy and the after bouncing back up to a height.

Initial mechanical energy is 10 + 0 = 10 J

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