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aleksandrvk [35]
4 years ago
5

Which of the following statements is true vibrations ?

Physics
1 answer:
Yuki888 [10]4 years ago
3 0

Answer:

<em>C. Neither ultrasonic nor infrasonic vibrations can be heard by humans.</em>

<em></em>

Explanation:

The complete question is

Which of the following statements is true of vibrations? A. The frequency of infrasonic vibrations is much too high to be heard by humans. B. Ultrasonic vibrations have a frequency lower than the range for normal hearing. C. Neither ultrasonic nor infrasonic vibrations can be heard by humans. D. Infrasonic vibrations are used in sonar equipment and to detect flaws in steel castings.

Ultrasonic vibrations have frequencies higher than our range of hearing, while infrasonic vibrations have frequencies lower than our range of hearing. Ultrasonic vibrations or sound is used in sonar equipment, and is used for detecting hidden flaws in steel castings and structures. Both infrasonic and ultrasonic fall below and above our normal hearing range respectively, and are only audible to dogs, cats, and some other mammals.

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Sophia is planning on going down an 8-m water slide. Her weight is 50 N. She knows that she has gravitational potential energy (
RideAnS [48]

Answer:

Explanation:

graph would be a straight line from (0, 0) to (400, 8)

Plot points are

PE = mgh

50(0) = 0 J

50(2) = 100 J

50(4) = 200 J

50(6) = 300 J

50(8) = 400 J

4 0
3 years ago
4. What two terms are sometimes used to indicate opposite directions from a point?
ivolga24 [154]
<h2><em>What two terms are sometimes used to indicate opposite directions from a point?</em></h2>

  • <em>The terms <u>positive and negative</u> can be useful when giving opposite directions from a reference point.</em>

<em>hope </em><em>it</em><em> helps</em>

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8 0
3 years ago
In doing a load of clothes, a clothes dryer uses 16 A of current at 240 V for 45 min. A personal computer, in contrast, uses 2.7
EastWind [94]

Answer:

(a) Total time will be 8.05 hour

(B) Total cost will be $417.6                

Explanation:

We have given dryer uses 16 A of current so current i = 16 A

Voltage V = 240 volt

Time t = 45 minutes =45×60 = 2700 sec

So power P = VI = 240×16 = 3840 W

So energy E = power×time = 3840×45×60 = 9396 KJ

(A) Now current in the computer i = 2.7 A

Voltage V = 120 V

So power P = 120×2.7 = 324 W

Now computer is using energy of dryer

So time by which it will use energy is t=\frac{9396000}{324}=29000sec=8.05hour

So time will be 8.05 hour

(b) Cost per kilowatt is $0.12

So total cost =3480×0.12 = $417.6

4 0
3 years ago
To tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.50•10^6 N, one at an angle 19.0° west of north, a
irina1246 [14]

Answer:

Work done by a tug boat, W = 1.735 x 10⁸ J

Explanation:

Given,

The of each tugboat, F = 1.5 x 10⁶ N

The angle of each tugboat forms with the resultant force, θ = 19°

The displacement of the supertanker, s = 710 m

The individual tugboat will be responsible for the displacement, d = 710/2

                                                                                                               = 355 m

The displacement component in each tugboat direction = 355 · sin θ meter

Therefore, the work done by each tugboat is

                                           W = F x S    joules

Substituting the values in the above equation

                                            W = 1.5 x 10⁶  x  355 · sin θ

                                                = 1.735 x 10⁸ J

Hence, the work done by each tugboat is, W = 1.735 x 10⁸ J                        

6 0
3 years ago
you stretch a spring by a distance of 0.3 m. the spring has a spring constant of 440 n/m. when you release the spring, it snaps
Alina [70]

Answer:

19.8 J

Explanation:

According to the law of conservation of energy, the total mechanical energy of the spring (sum of kinetic energy and elastic potential energy) must be conserved:

K_i + U_i = K_f + U_f (1)

where we have

K_i is the initial kinetic energy of the spring, which is zero because the spring starts from rest (2)

U_i is the elastic potential energy of the spring when it is fully stretched

K_f is the kinetic energy of the spring when it reaches the natural length

U_f is the elastic potential energy of the spring when it reaches its natural length, which is zero because the stretch in this case is zero (3)

So

U_i = \frac{1}{2}k(\Delta x_i)^2

where

k = 440 N/m is the spring constant

\Delta x_i = 0.3 m is the initial stretching of the spring

Substituting,

U_i = \frac{1}{2}(440)(0.3)^2=19.8 J

And so using eq.(1) and keeping in mind (2) and (3) we find

K_f= U_i = 19.8 J

8 0
3 years ago
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