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alexandr1967 [171]
2 years ago
9

A puppy weighs​534​pounds.

Mathematics
1 answer:
Over [174]2 years ago
5 0
The puppy weighs 92 oz
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A bamboo plant grows about 1.26 feet each
JulsSmile [24]

Answer:

8.82 feet in one week hopes it's helps

5 0
3 years ago
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The equation of a line is y = 2x − 6. Find the slope and y-intercept of the line.
SCORPION-xisa [38]

Answer:

Slope is 2 and y-int is -6

Step-by-step explanation:

y=mx+b

M is slope

B is y-int

7 0
3 years ago
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Simplify u^2+3u/u^2-9<br> A.u/u-3, =/ -3, and u=/3<br> B. u/u-3, u=/-3
VashaNatasha [74]
  The correct answer is:  Answer choice:  [A]:
__________________________________________________________
→  "\frac{u}{u-3} " ;  " { u \neq ± 3 } " ; 

          →  or, write as:  " u / (u − 3) " ;  {" u ≠ 3 "}  AND:  {" u ≠ -3 "} ; 
__________________________________________________________
Explanation:
__________________________________________________________
 We are asked to simplify:
  
  \frac{(u^2+3u)}{(u^2-9)} ;  


Note that the "numerator" —which is:  "(u² + 3u)" — can be factored into:
                                                      →  " u(u + 3) " ;

And that the "denominator" —which is:  "(u² − 9)" — can be factored into:
                                                      →   "(u − 3) (u + 3)" ;
___________________________________________________________
Let us rewrite as:
___________________________________________________________

→    \frac{u(u+3)}{(u-3)(u+3)}  ;

___________________________________________________________

→  We can simplify by "canceling out" BOTH the "(u + 3)" values; in BOTH the "numerator" AND the "denominator" ;  since:

" \frac{(u+3)}{(u+3)} = 1 "  ;

→  And we have:
_________________________________________________________

→  " \frac{u}{u-3} " ;   that is:  " u / (u − 3) " ;  { u\neq 3 } .
                                                                                and:  { u\neq-3 } .

→ which is:  "Answer choice:  [A] " .
_________________________________________________________

NOTE:  The "denominator" cannot equal "0" ; since one cannot "divide by "0" ; 

and if the denominator is "(u − 3)" ;  the denominator equals "0" when "u = -3" ;  as such:

"u\neq3" ; 

→ Note:  To solve:  "u + 3 = 0" ; 

 Subtract "3" from each side of the equation; 

                       →  " u + 3 − 3 = 0 − 3 " ; 

                       → u =  -3 (when the "denominator" equals "0") ; 
 
                       → As such:  " u \neq -3 " ; 

Furthermore, consider the initial (unsimplified) given expression:

→  \frac{(u^2+3u)}{(u^2-9)} ;  

Note:  The denominator is:  "(u²  − 9)" . 

The "denominator" cannot be "0" ; because one cannot "divide" by "0" ; 

As such, solve for values of "u" when the "denominator" equals "0" ; that is:
_______________________________________________________ 

→  " u² − 9 = 0 " ; 

 →  Add "9" to each side of the equation ; 

 →  u² − 9 + 9 = 0 + 9 ; 

 →  u² = 9 ; 

Take the square root of each side of the equation; 
 to isolate "u" on one side of the equation; & to solve for ALL VALUES of "u" ; 

→ √(u²) = √9 ; 

→ | u | = 3 ; 

→  " u = 3" ; AND;  "u = -3 " ; 

We already have:  "u = -3" (a value at which the "denominator equals "0") ; 

We now have "u = 3" ; as a value at which the "denominator equals "0"); 

→ As such: " u\neq 3" ; "u \neq -3 " ;  

or, write as:  " { u \neq ± 3 } " .

_________________________________________________________
6 0
3 years ago
Which shows a correct order to solve this story problem? Maxine had to pay $1.46 in sales tax on her purchases. She bought 3 bar
romanna [79]
Choice B would be the correct answer. I hope that helps! :D
4 0
3 years ago
Select all that apply.Several pennies are tossed in the air. Twelve land heads up and fifteen land tails up. Which of the follow
OverLord2011 [107]
The information we've been given is:

12 heads
15 tails

From those, we find that there are 12 + 15 = 27 coins.

Let's examine these ratios as such:

- 12 heads to 27 coins -
There are indeed 12 heads and 27 coins, so this comparison agrees with our data.

- 15 tails to 12 heads - 
Again, nothing here contradicts with our data, so this would be correct as well

- 12 heads to 15 tails -
Simply a reversed version of the ratio above; still a completely valid way to compare the relative quantities of heads and tails

- 5 tails to 9 coins -
This one needs a little more examination. We observe that the ratio of tails to coins with our given data is 15 tails to 27 coins. This seems to go against our data, but we can simplify our ratio by dividing both the number of tails and the number of coins by 3, which indeed gives us the ratio 5 tails to 9 coins.

So, all of the given ratios are correct.
3 0
3 years ago
Read 2 more answers
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