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Sever21 [200]
3 years ago
14

What are two key characteristics of a good scientific investigation

Chemistry
1 answer:
AfilCa [17]3 years ago
8 0
There are more than two! Let's mention some: including experiments and observations into the study, having a control condition, closely following the devised procedure, having a hypothesis, etc...
You might be interested in
How many moles of Manganese there in are 5.76 x 10(15) atoms of Mn?
aksik [14]

Answer:

1. 9.57 × 10^-9 moles.

2. 7.38mol

Explanation:

1.) To find the number of moles there are in the number of particles in an atom, we divide the number of particles (nA) by Avagadro's constant (6.02 × 10^23)

Hence, to find the number of moles (n) of Manganese (Mn), we say:

5.76 x 10^15 atoms ÷ 6.02 × 10^23

5.76/6.02 × 10^(15-23)

= 0.957 × 10^-8

= 9.57 × 10^-9 moles.

2.) Mole = mass/molar mass

Molar mass of sodium chloride (NaCl) = 23 + 35.5

= 58.5g/mol

mole = 431.6 g ÷ 58.5g/mol

mole = 7.38mol

7 0
3 years ago
Whats the balanced equation for sodium hydroxide + ammonium sulphate=sodium sulphate + amonia + h2o​
Nady [450]

Answer:

2NaOH + (NH4) 2SO4 = Na2SO4(s) + 2NH3(g) + 2H2O(l)

Two moles of sodium hydroxide reacts with 1 Mike of ammonium sulphate to give 1 mole of Sodium sulphate, 2 moles of ammonia gas and 2 moles of water

Explanation:

7 0
3 years ago
Which of the following steps in a star's life cycle takes the longest?
Vsevolod [243]
<span>The correct anwser is "C.fusion of hydrogen atoms"</span>
4 0
3 years ago
Is carbonic acid (H2CO3) soluble in water?
NeTakaya

Answer:

it is soluble in water

Explanation:

mark brainliest pliiz cutee:)

8 0
3 years ago
Read 2 more answers
At 350°c, keq = 1.67 × 10-2 for the reversible reaction 2hi (g) ⇌ h2 (g) + i2 (g). what is the concentration of hi at equilibriu
mariarad [96]
According to the reversible reaction equation:

2Hi(g) ↔ H2(g) + i2(g)

and when Keq is the concentration of the products / the concentration of the reactants.

Keq = [H2][i2]/[Hi]^2

when we have Keq = 1.67 x 10^-2

[H2] = 2.44 x 10^-3

[i2] = 7.18 x 10^-5

so, by substitution:

1.67 x 10^-2 = (2.44 x 10^-3)*(7.18x10^-5)/[Hi]^2

∴[Hi] = 0.0033 M
7 0
3 years ago
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