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Sever21 [200]
3 years ago
14

What are two key characteristics of a good scientific investigation

Chemistry
1 answer:
AfilCa [17]3 years ago
8 0
There are more than two! Let's mention some: including experiments and observations into the study, having a control condition, closely following the devised procedure, having a hypothesis, etc...
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PLEASE HELP ME THIS IS DUE RN I HAVE NO IDEA I WILL MARK BRAINLIEST I JUST NEED HELP
djverab [1.8K]

Answer:

3.45 × 10^5

=3.45^5

I hope this helps

6 0
3 years ago
Using the following reaction (depicted using molecular models), large quantities of ammonia are burned in the presence of a plat
Mila [183]

Answer:

17.65 grams of O2 are needed for a complete reaction.

Explanation:

You know the reaction:

4 NH₃ + 5 O₂ --------> 4 NO + 6 H₂O

First you must know the mass that reacts by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction). For that you must first know the reacting mass of each compound. You know the values ​​of the atomic mass of each element that form the compounds:

  • N: 14 g/mol
  • H: 1 g/mol
  • O: 16 g/mol

So, the molar mass of the compounds in the reaction is:

  • NH₃: 14 g/mol + 3*1 g/mol= 17 g/mol
  • O₂: 2*16 g/mol= 32 g/mol
  • NO: 14 g/mol + 16 g/mol= 30 g/mol
  • H₂O: 2*1 g/mol + 16 g/mol= 18 g/mol

By stoichiometry, they react and occur in moles:

  • NH₃: 4 moles
  • O₂: 5 moles
  • NO: 4 moles
  • H₂O: 6 moles

Then in mass, by stoichiomatry they react and occur:

  • NH₃: 4 moles*17 g/mol= 68 g
  • O₂: 5 moles*32 g/mol= 160 g
  • NO: 4 moles*30 g/mol= 120 g
  • H₂O: 6 moles*18 g/mol= 108 g

Now to calculate the necessary mass of O₂ for a complete reaction, the rule of three is applied as follows: if by stoichiometry 68 g of NH₃ react with 160 g of O₂, 7.5 g of NH₃ with how many grams of O₂ will it react?

mass of O_{2} =\frac{7.5 g of NH_{3} * 160 g of O_{2} }{68 g of NH_{3} }

mass of O₂≅17.65 g

<u><em>17.65 grams of O2 are needed for a complete reaction.</em></u>

3 0
3 years ago
Determine the molecular formula of a compound having the empirical formula C9H17O and a molar mass of 847.56g/mol.
Arlecino [84]
 The  molecular  formula of a compound  having  the empirical  formula  C9H17O  is calculated as below

(C9H17O)n =847.56

{(12 x9 + 1 x17 + 1 x16)}n= 847.56

147 n = 847.56
divide bot
h side by 147
n= 6

(C9H17O)6 therefore the molecular formula = C54H102O6
7 0
4 years ago
Find the empirical formula of the compound which contains 67.6% Hg, 10.8% S, and 21.6% O.
WINSTONCH [101]

Explanation:

Divide 67.6% by 201 of mercury

Divide 10.8% by 32 of sulfur

Divide 21.6% by 16 of oxygen

Then divide number by itself .

Example : Divide 2.97 by both sulfer moles and oxygen moles . Multiply by 2 to get whole number

7 0
3 years ago
For the following word equations, write it as a chemical equation, then balance it.
Naddik [55]

CuO+H2=Cu+H2O the equation is balanced.

6 0
3 years ago
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