C. N₂ + 3H₂ → 2NH₃
In a redox, or oxidation-reduction, reaction, one of the reactants must be reduced, which means its oxidation number decreases, while the other reactant must be oxidized, which means its oxidation number increases. The oxidation number of nitrogen in the reactants is 0 and is -3 in the products, so it is reduced. Similarly, the oxidation number of hydrogen is 0 in the reactants but it is +1 in the products.
Answer:
Bind to the protein complex troponin.
Explanation:
Excitation of skeletal muscle caused by the calcium ions. During excitation of skeletal muscle, after calcium ions released into the cytosol, they bind to the protein complex known as troponin and causing substitutions in the protein complex.
These alterations permit protein to push out from the myosin-binding sites on the actin filament.
Answer:
The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.
Explanation:
Assume that ethane behaves as an ideal gas under these conditions.
By the ideal gas law,
,
.
where
is the pressure of the gas,
is the volume of the gas,
is the number of moles of particles in this gas,
is the ideal gas constant, and
is the absolute temperature of the gas (in degrees Kelvins.)
The numerical value of will be 
if , , and are in SI units. Convert these values to SI units:
;- shall be in cubic meters,
; 
.
Apply the ideal gas law:
.
Answer:
5. The valence electrons of both fluorine and carbon are found at about the same distance from their respective nuclei but the greater positive charge of the fluorine nucleus attracts its valence electrons more strongly.
Explanation:
Both fluorine and carbon are located in the second period of the periodic table, it means that they have 2 shells, so the valence electrons are found at about the same distance from their respective nuclei.
But fluorine has a higher atomic number, 9, than the carbon, 6. The atomic number represents how many protons there are in the nucleus, then there are more protons (positive charge) at the fluorine nucleus, and because of that, the attraction force between the nucleus and the valence electron is stronger in fluorine.
If the force is stronger, it will be necessary more energy to break the bond, so it will be harder to remove an electron from fluorine than from carbon.
Answer:
It might the nucleus
Explanation:
Because proton and neutron are both in the nucleus of an atom.
