Hi please help......
1 answer:
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Answer:
x= 1, x= 4, and x= -3
Step-by-step explanation:
Use the possible combinations of factors of the constant term of the polynomial to find a first root. Try 1, -1, 2, -2, 3, -3, etc.
Notice in particular that x = 1 is a root (makes f(1) = 0):
So we know that x=1 is a root, and therefore, the binomial (x-1) must divide the original polynomial exactly.
As we perform the division, we find that the remainder of it is zero (perfect division) and the quotient is:
This is now a quadratic expression for which we can find its factor form:
From the factors we just found, we conclude that x intercepts (zeroes) of the original polynomial are those x-values for which each of the factors: (x-1), (x-4) and (x+3) give zero. That is, the values x= 1, x= 4, and x= -3. (these are the roots of the polynomial.
Mark these values on the number line as requested.
Assuming you want the equation in slope intercept form, you first need to use slope formula to find the slope.
Plug in the coordinates that you have, (3,-1) and (4,7), for the x and y values respectively.
Which reduces to 8/1=8.
The slope of your equation is 8.
Slope intercept form is: y=mx+b. m is your slope and b is your y-intercept, x and y stay unchanged.
Plug the slope in:
y=8x+b.
Now, you can plug one of the sets of coordinates into the x and y of the equation to find b. I'm using (3,-1).
-1=8(3)+b
-1=24+b
Subtract 24 from both sides.
-25=b
Now plug this into the equation!
y=8x-25 is your final equation.
I hope this helps :)