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qwelly [4]
2 years ago
15

Factorise fully 9b-3b2

Mathematics
1 answer:
alexdok [17]2 years ago
3 0

Answer:

3b(3-b) is the answer

Step by step explanation : take out the most common factor which is 3b

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What is the solution to 3.2x = 6.4?
jeyben [28]
A. X = 2 
what you do is divide each side by the coefficient of x (3.2) to get rid of it on the left, and simplify the right: 2.

6 0
3 years ago
What is another way to write the expression ​ t⋅(14−5) ​?
grigory [225]

t⋅(14−5)

distribute

14t -5t

Choice A

8 0
3 years ago
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The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

5 0
3 years ago
Simplify The Expression:<br><br> 1/8h+7-3/4h<br><br> Thank you!
ivann1987 [24]

Answer:

-5/8h + 7

Step-by-step explanation:

First you need to combine like terms (1/8h and -3/4h)

So 1/8h - 3/4h is -5/8h

Then we have our 7 left over

So the answer is -5/8h + 7

4 0
3 years ago
I need help I forgot all about this and I would appreciate it!
miskamm [114]

Answer:

$3.75

Step-by-step explanation:

You only have to multiply 3 pounds by the $1.25 to get the cost.

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2 years ago
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