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Ghella [55]
3 years ago
9

What is the mode of the data shown in the following dot plot?

Mathematics
1 answer:
Lilit [14]3 years ago
7 0

4

Step-by-step explanation:

mode is the number appearing the most

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PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ
Lostsunrise [7]

Answer:

90 degrees

Step-by-step explanation:

x= 90° angle of the right triangle

So, x= 90 degrees

3 0
3 years ago
PLEASE RESPOND! !!
cestrela7 [59]

Answer:

36/132

Step-by-step explanation:

36/132, .27, 27%...

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4 years ago
2/7 decimal from rounded to the nearest thousandth place
Wewaii [24]

Answer:

0.286

Step-by-step explanation:

2/7 as a decimal is 0.28571429

0.28571429 rounded to thousandths place = 0.286

hope this helps!!!

8 0
3 years ago
Lucy graphed the relationship between the temperature and the change in the number of people sledding at a park. The xxx-coordin
Shalnov [3]

Answer: quadrant 1

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Can anyone do 4,5 and 6 for me plz
cricket20 [7]

For  question 4, sinA =\frac{a}{c}, cosA= \frac{b}{c}, tan B = \frac{b}{a}, sin J = \frac{j}{l}, cosK = \frac{j}{l}, tanK = \frac{k}{j}.

Question 5. Option a and question 6. Option j

Step-by-step explanation:

Step 1:

The three basic formula needed to solve these questions are:

sin\theta = \frac{oppositeside}{hypotenuse} , cos\theta = \frac{adjacentside}{hypotenuse}, tan\theta= \frac{opposite side}{adjacent side}.

Step 2:

Using the above formula, we solve the following values

sinA = \frac{oppositeside}{hypotenuse}  =\frac{a}{c}.

cosA = \frac{adjacentside}{hypotenuse} = \frac{b}{c}.

tanB= \frac{opposite side}{adjacent side}= \frac{b}{a}.

sinJ = \frac{oppositeside}{hypotenuse} = \frac{j}{l}.

cosK = \frac{adjacentside}{hypotenuse}= \frac{j}{l}.

tanK= \frac{opposite side}{adjacent side}= \frac{k}{j}.

Step 3:

For question 5, The triangle's angle = 23°, opposite side = BC inches and hypotenuse = 4 inches.

sin\theta= \frac{opposite side}{hypotenuse}. sin 23^{\circ}= \frac{BC}{4}, sin23^{\circ} = 0.3907,BC = (0.3907)(4) = 1.5628.

SO BC is 1.5628 inches, rounding this off to the nearest tenth, we get BC = 1.6 inches which is option a.

Step 4:

For question 6, The triangle's angle = 50°, opposite side = QR m the adjacent side = 8.1 m.

tan\theta= \frac{opposite side}{adjacentside}. tan 50^{\circ}=\frac{QR}{8.1}, tan50^{\circ} = 1.1917,QR = (1.1917)(8.1) = 9.65277

SO QR is 9.65277 meters, rounding this off to the nearest tenth, we get QR = 9.7 inches which is option j.

7 0
3 years ago
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