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Ghella [55]
3 years ago
9

What is the mode of the data shown in the following dot plot?

Mathematics
1 answer:
Lilit [14]3 years ago
7 0

4

Step-by-step explanation:

mode is the number appearing the most

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Help plzzzzzzzzzzzzzzzzzzzz
bulgar [2K]

Answer:

y = -4

Step-by-step explanation:

First, let's find the slope. Since the line is horizontal, it's slope has to be 0 (this is because slope = rise/run, there is no "rise" in a horizontal line therefore the slope is 0)

Now, we need to find the y-intercept. This is where the line intercepts the y-axis. Looking at the graph, the line intercepts the axis at (0,-4), therefore the y-intercept is -4.

The equation would be:

y=0x-4

y=-4

5 0
2 years ago
Estimate how to find 15% tip on $9.79 explain your thoughts
uranmaximum [27]
(15/100) then multiply that with 9.79 and you get $1.4685, which is the answer
5 0
3 years ago
Read 2 more answers
In a regular 52 deck of cards, what is the probability of picking a random spade, a 4 of any suit and then a random diamond with
meriva

sample \: space = 52 \: cards \\ spades = 13 \: cards \\ number \: 4s = 4 \: cards \\ diamonds = 13 \: cards \\ note \: that =  \\ there \: is \: replacement \\ order \: does \: matter

P( \gamma ) =  \frac{13}{52}  \times  \frac{4}{52}  \times  \frac{13}{52}  =  \frac{1}{208}

5 0
2 years ago
[25 POINTS] PLEASE HELP ME! QUICK AND EASY POINTS! ALL INFO IS IN THE IMAGE!
lbvjy [14]

Answer:

Where's the image?

Step-by-step explanation:

4 0
2 years ago
For what values of x is log base 0.8 (x+4)&gt;log base 0.4 (x+4)<br>Thank you!
Radda [10]
We are seeking the solution of the inequality:

\displaystyle{ \log_{0.8}(x+4)\ \textgreater \ \log_{0.4}(x+4).


We recall that a log function f(x)=\log_b(x) is either increasing or decreasing:

i) it is increasing if b>1, 

ii) it is decreasing if 0<b<1.

Consider the functions \displaystyle{ \log_{0.8}(x) and \displaystyle{ \log_{0.4}(x).

The graphs of these functions both meet at x=1 (clearly), and after 1 they are both negative. So from 0 to 1 one of them is larger for all x, and from 1 to infinity the other is larger. (Being strictly decreasing, their graphs can only intersect once.)


We can check for a certain convenient point, for example x=0.8:

\displaystyle{ \log_{0.8}(0.8)=1 and

\displaystyle{ \log_{0.4}(0.8)=\log_{0.4}(0.4\cdot 2)=\log_{0.4}(0.4)+\log_{0.4}(\cdot 2)=1+\log_{0.4}(2).

Now, \displaystyle{ \log_{0.4}(2) is negative since we already explained that for x>1 both functions were negative. This means that 

\displaystyle{ \log_{0.8}(0.8)\ \textgreater \ \log_{0.4}(0.8), and since 0.8\in (0, 1), then this is the interval where \displaystyle{ \log_{0.8}(x)\ \textgreater \ \log_{0.4}(x).


So, now considering the functions \displaystyle{ \log_{0.8}(x+4) and \displaystyle{ \log_{0.4}(x+4), we see that 

x+4 must be in the interval (0,1), so we solve:

0<x+4<1, which yields -4<x<-3 after we subtract by 4.


Answer: (-4, -3). Attached is the graph generated using Desmos.

7 0
3 years ago
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