All categories

3 years ago

I need help with this

Mathematics

2 answers:

Sedbober [7]3 years ago

8 0

The answer is 5
step by step explanation

-BARSIC- [3]3 years ago

6 0

Answer:

Step-by-step explanation:

3 + 6 * 4 - 80 / 10 + 4 - 18 = 3 + 24 - 8 + 4 - 18 = 27 - 8 + 4 - 18 = 19 + 4 -18 = 23 - 18 = 5

You might be interested in

(-1) + (-1) + (-1) + (-1) + ... 500 times =<br>(a) 500<br>(b) 1<br>(c) -1<br>(d) -500

pickupchik [31]

Answer:

Step-by-step explanation:

(-1) + (-1) = -2... so 500 times... it would be -500.

4 0

3 years ago

Mention Two properties of magnets Pls tell me fastttt I want to write

VMariaS [17]

I hope it helped youuuuuu

4 0

3 years ago

Which polynomial can be simplified to a difference of squares

Mrrafil [7]

<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)$

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

$First=10a^{2}$

$Second=16a^{2}$

$Third=25a^{2}$

$Fourth=24a^{2}$

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

$16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}$

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

$16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)$

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

$25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}$

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}$

7 0

3 years ago

Read 2 more answers

Solve the following system of equations using the substitution method.

BartSMP [9]

Answer:

Step-by-step explanation:

First label the equations.

6x +3y= 18 -----(1)

y= -2x +5 -----(2)

subst. (2) into (1):

6x +3(-2x +5)= 18

6x +3(-2x) +3(5)= 18 (expand)

6x -6x +15= 18

15= 18 (simplify)

(reject)

There is no solution.

<u>Further explanation</u><u>:</u>

If I rewrite the first equation into the form of y=mx+c, I would get

6x +3y=18

3y= 18 -6x (bring y term to one side)

y= 6- 2x (÷3 throughout)

y= -2x +6

Notice that the gradients of both lines are equal ( -2). This implies that they are parallel to each other and will never meet. Hence there are no solutions.

3 0

3 years ago

Rectangle ABCD was dilated to create rectangle A'B'C'D. Triangle A B C D is dilated to form triangle A prime B prime C prime D.

Julli [10]

Answer:

$AB = 6$