Answer:
a = 17.81 m/s²
Explanation:
Given that,
Shaun and his friend give Shirley a big shove all at once, applying a force of F=980 N
Let us assume that the mass of Shaun and his friend is 55 kg.
Let a is the acceleration during this shove.
The second law of motion is given by :
F = ma
So, the acceleration of Shirley is 17.81 m/s².
Mechanical digestion..............
Answer: 2.55 joules, -9.81 joules, -12.36 joules
Explanation:
the parameters given from the question are :
mass (m) = 0.20 kg
height above water (h₁) = 1.3m
depth of the well (h₂) = 5m = -5m (the negative sign is there because it is a depth below the surface )
constant value for acceleration due to gravity (g) = 9.8 m/s
- potential energy (PE) before the stone is released = m x g x h₁
PE₁ = 0.20 x 9.8 x 1.3 = 2.55 joules
- potential energy (PE) when it reaches the bottom of the well= m x g x h₂
PE₂ = 0.2 x 9.8 x (-5) = -9.81 joules
- change in potential energy = PE₂ - PE₁
= -9.81 - 2.55 = -12.36 joules
Answer:
(A) 1.01 s
(B)
Explanation:
horizontal distance (L) = 3 m
vertical height (h) = 1.25 m
acceleration due to gravity (g) = 9.8 m/s^{2}
(A) hang time refers to how long the person remains in the air, and is the summation of the time it took attain maximum height and the time it takes to get back to the ground.
- it is going to take the same amount of time to attain maximum height and to return to the ground.
- from s = ut + 0.5g we can get the time taken to attain maximum height.
where s = vertical distance = 1.25 m
u = initial velocity = 0 (since body starts from rest)
g = acceleration due to gravity = 9.8 m/s^{2}
t == time taken to get to maximum height
the equation now becomes s = 0.5g
1.25 = 0.5 x 9.8 x
= 1.25/(0.5x9.8)
t =
t = 0.505 s
- now that we have the time taken to attain maximum height which is also equal to the time it takes to get back to the ground.
total time = time taken to attain maximum height + time it takes to get back to the ground.
total time = 0.505 + 0.505 = 1.01 s
(B) when horizontal distance = 6 m , the hang time would remain the same, because the horizontal component does not affect the vertical component . Also we can see that from the equation used in part A above the horizontal component was not used to solve for the time. Therefore hang time = 1.01 s
In order to form a real image using a concave mirror, the object must be placed beyond the center of curvature of the mirror. Therefore, the object must be further from the mirror than the focal point. The image that will form will be real, but it will also be inverted and its magnification will be less than 1, meaning it will be smaller than the actual object.