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alexandr402 [8]
3 years ago
5

Part 1

Physics
1 answer:
nlexa [21]3 years ago
3 0

The force exerted by the hammer claws on the nail is =1578N

<h3 /><h3>How to calculate magnitude of force:</h3>

The force that is applied, as the effort on the hammer= F1

The force exerted by the hammer claws on the nail= F2

But,

magnitude of force exerted on hammer= F1*d1

While magnitude of force exerted by the hammer claws on the nail = F2( d2sin30°)

And, F1*d1 = F2( d2sin30°)

Where F1 = 133N

d1 = 29cm = 0.29m

F2 = X

d2 = 4.89cm = 0.0489m

After substitution,

133 × 0.29 = X( 0.0489 × sin30°)

38.57 = X ( 0.0489 × 0.5)

38.57 = X(0.02445)

X= 38.57/0.02445

X = 1578N

Therefore, the force exerted by the hammer claws on the nail is =1578N

Learn more about force here:

brainly.com/question/25239010

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