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4 years ago

Does a car accelerate when it goes around a corner at a constant speed?

1 answer:

6 0

Yes, it does. Acceleration is defined as the rate of change of velocity. Velocity is the rate of change of position with a given direction i.e. speed with direction.So even though the speed of the turning car is constant the velocity is not. This means that the velocity is changing, and the rate of change of velocity is called acceleration. Hence, the car is accelerating.

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How does the centre of gravity vary with different objects?

Aliun [14]

Answer:

The point through which the Whole mass of the body acts, irrespective of the position of the body, is known as centre of gravity (briefly written as c.g.). ... Mass affects the centre of gravity of the object.

Explanation:

5 0

3 years ago

A 5 kg brick is dropped from a height of 12m on a spring with a spring constant 8 kN/m. If the spring has unstretched length of

Ivan

Answer:

0.1164 m

0.49387 m

Explanation:

m = Mass = 5 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Height from which brick falls = 12 m

k = Spring constant = 8 kN/m

a) Potential energy of the brick

$PE=mgh\\\Rightarrow PE=5\times 9.81\times 12\\\Rightarrow PE=588.6\ J$

Potential energy in spring

$PE=\frac{1}{2}\times kx^2\\\Rightarrow x=\sqrt{\frac{PE\times 2}{k}}\\\Rightarrow x=\sqrt{\frac{588.6\times 2}{8000}}\\\Rightarrow x=0.3836\ m$

The compression of spring = 0.5-0.3836 = 0.1164 m

b) Weight of the brick

$F=5\times 9.81\\\Rightarrow F=49.05\ N$

$F=kx\\\Rightarrow x=\frac{F}{k}\\\Rightarrow x=\frac{49.05}{8000}\\\Rightarrow x=0.00613\ m$

The final length of the spring = 0.5-0.00613 = 0.49387 m

4 0

3 years ago

Calculate the average power required to lift a 490-newton object a vertical distance of 2.0 meters in 10. seconds. [Show all wor

bagirrra123 [75]

For this problem, you should be able to differentiate the variables presented from each other in order to substitute them in their corresponding places in the formula or formulas to be utilized in this problem. As for this problem, the only formula to be utilized would be the formula for power which is force multiplied to distance over time or simply have force multiplied to speed since speed is equal to distance over time.

The formula would like this:

Power = force x distance / time Power = force x speed

P = 490 N x 2 m / 10 s P = 490 N x (2 m / 10 s)
P = 980 N m / 10 s P = 490 N x 0.2 m / s
P = 98 W P = 98 W

So the average power required to lift a 490-newton object a vertical distance of 2.0 meters in 10 seconds would be 98 watts.

3 0

3 years ago

A glass rod was charged positively by rubbing it with neutral silk, then the rod was touched to the top of a neutral electroscop

Leto [7]

D is ur answer bc th ngeavtixe would pull the electric or

5 0

3 years ago

What is f if you have an object 2.0 m from the concave mirror, and the image is 4.0 m from the mirror?

dezoksy [38]

Answer:

the f is 1.3 m

Explanation:

Given that

An object 2.0m is from the concave mirror

And, the image is 4.0m from the mirror

We need to find out the f

So,

u = -2 m

v = -4 m

1 ÷ f = 1 ÷ v + 1 ÷ u

= (-1 ÷ 4) + (-1 ÷ 2)

= -3 ÷4

f = -4 ÷ 3

= |1.3| m

Hence, the f is 1.3 m

7 0

3 years ago