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Readme [11.4K]
3 years ago
8

A 33 kg gun is standing on a frictionless surface. The gun fires a 57.7g bullet with a muzzle velocity of 325m/s. The positive d

irection is that of the bullet.
Calculate the kinetic energy of thebullet immediately after the gun was fired. Answer in units of J
Physics
1 answer:
Stella [2.4K]3 years ago
7 0
Kinetic Energy =  (1/2) mv^2.

m = 57.7 g = 57.7/1000 = 0.00577 kg.
v = 325 m/s.

E = 0.5 * 0.00577 * 325^ 2.    Use your calculator.

E = 304.728125  J.

That's the kinetic energy.
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Via half-life equation we have:


A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h} }


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A_{final}=50(\frac{1}{2})^\frac{12}{4}=50(\frac{1}{2})^{3}=50(\frac{1}{8})=6.25g


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328,000 mm + 137 m = ______________m?
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Answer:

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Explanation:

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Answer:

a) (Qa*g*Vb)-(Qh*Vb*g)=(Qh*Vb*a)\\where \\g=gravity [m/s^2]\\a=acceleration [m/s^2]

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The total mass of the balloon is:

massball=densityheli*volumeheli\\\\massball=0.41 [kg/m^3]*0.048[m^3]\\massball=0.01968[kg]\\\\

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Now we need to make a free body diagram where we can see the forces that are acting over the balloon and determinate the acceleration.

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Answer:

Two point charges are separated by 6.4 cm . The attractive force between them is 10 N .

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