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Readme [11.4K]
3 years ago
8

A 33 kg gun is standing on a frictionless surface. The gun fires a 57.7g bullet with a muzzle velocity of 325m/s. The positive d

irection is that of the bullet.
Calculate the kinetic energy of thebullet immediately after the gun was fired. Answer in units of J
Physics
1 answer:
Stella [2.4K]3 years ago
7 0
Kinetic Energy =  (1/2) mv^2.

m = 57.7 g = 57.7/1000 = 0.00577 kg.
v = 325 m/s.

E = 0.5 * 0.00577 * 325^ 2.    Use your calculator.

E = 304.728125  J.

That's the kinetic energy.
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If you connected 10 of these 12V (10 W) lamps in parallel, to the 12V source, how much current would the source have to supply
Flauer [41]

Answer:

T=8.33A

Explanation:

From the question we are told that:

Number of battery n=10

Voltage sourceE=12V

Lamp PowerP=10W

Generally the equation for Resistance is mathematically given by

 R=\frac{V^2}{P}

 R=\frac{12^2}{10}

 R=14.4ohms

Therefore

 R_{eq}=\frac{14.4}{10}

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Generally the equation for Current is mathematically given by

 T=\ffrac{V}{Req}

 T=\frac{12}{1.44}

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6 0
2 years ago
a bicycle travels at a velocity of -2.33 m/s and has a displacement of -58.3 m. how much time did it take?
Alexandra [31]
We know that velocity is equal to the total displacement of an object over time.
velocity =  \frac{displacement}{time}
Deriving from that equation, we can say that:
t =  \frac{d}{v}
Okay, so here it goes:
t =  \frac{58.3m}{2.33 \frac{m}{s} } \\ t = 25.02s
The bicycle took 25.02 seconds to displace at 58.3 meters.
5 0
3 years ago
SP: Calculate the moment
ipn [44]

Answer:

Moment of the force is 20 N-m.

Explanation:

Given:

Force exerted by the person is, F=80\ N

Distance of application of force from the point about which moment is needed is, d=25\ cm=\frac{25}{100}\ m=0.25\ m

Now, we know that, moment of a force 'F' about a point at a perpendicular distance of 'd' from the same point is given as the product of the force and the perpendicular distance.

Therefore, the moment of the force about the end of the claw hammer is given as:

M=F\times d\\\\M=(80\ N)(0.25\ m)\\\\M=20\textrm{ N-m}

Hence, the moment of the force exerted by the person about the end of the claw hammer is 20 N-m.

6 0
3 years ago
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