Answer:
The final pressure will double i.e it will be twice the initial pressure
Explanation:
T1 = T
T2 = 2T ( twice the original T)
P1 = P
P2 =?
Since the volume is constant,
P1/ T1 = P2 /T2
P/ T = P2 / 2T
Cross multiply
T x P2 = 2T x P
Divide both side by T
P2 = (2T x P) / T
P2 = 2P
Therefore, the final pressure will double i.e it will be twice the initial pressure
Answer:
a) [NH2]-,
b) [O]2-
c) [Cl]-
Explanation:
The conjugate base is the base member (X⁻) of a weak acid (HX). In other words, the conjugate base is the remaining substance due to the proton loss in the acid HX.
a) For NH₃, (HX; X: NH₂⁻), conjugate base is NH₂⁻. In the format, <em>[NH2]-</em>.
b) For OH⁻, (HX; X: O²⁻), conjugate base is O²⁻. In the format,<em> [O]2-</em>.
c) For HCl, (HX; X: Cl⁻), conjugate base is Cl⁻. In the format, <em>[Cl]-</em>.
Answer:
C. Atoms of elements with five to seven valence electrons form anions in order to meet the octet rule.
Explanation:
- Atoms of elements gain or lose electron(s) to obey the octet rule by forming cations or anions.
- Atoms with 1 to 3 valence electrons lose electrons to form cations in order to attain a stable configuration.
- Atoms with 5 to 7 valence electrons gain electron(s) to form anions in order to attain stable configuration.
- However, atoms with 8 valence electrons do not require to gain or lose electrons since they an octet configuration.
- Atoms of metallic elements such as those in group 1 and 2 lose electron(s) to form cations while atoms of non-metallic elements such as halogens require to gain electron(s) to form anions so as to obey the octet rule.
