Answer:
Yes
Explanation:
An object's weight can change, depending on its location, relative to the object of discussion. For example, we don't notice the change, but the farther away we are from Earth's core, the less we weigh. This means one would weigh more in a valley than they would on a mountain. The formula for gravity is F=G((msub1)(msub2)/r^2), where F is the force of attraction, G is the universal gravitational constant, msub1 is the mass of the first object, msub2 is the mass of the second object, and r is the distance between the two objects.
Answer:
Matter is the term for any type of material. Matter is anything that has mass and takes up space. At a minimum, matter requires at least one subatomic particle, although most matter consists of atoms.
Some examples are: Water, books, pencils, sun, earth, moon, electron, proton, mesons, and quarks
Answer:
328.4KJ
Explanation:
Before we move on to calculate enthalpy change, we calculate the amount of heat Q
Q= mcΔT
m = density * volume = 250 * 1.25 = 312.5g
c = 3.74J/g.k
ΔT = 7.80 + 273.15K = 280.95K
Q= 312.5 * 3.74 * 280.95 = 328,360.312 J= 328.4KJ(1000J = 1KJ, so divide by 1000)
The enthalpy change in the reaction is same as amount of heat transferred = 328.4KJ
The oxidation half equation is Zn ------> Zn^2+ + 2e while the reduction half equation is Cu^2+ + 2e------> Cu.
A redox reaction is a reaction in which there is a loss/gain of electrons. The specie that gives out electrons experiences an increase in oxidation number while the specie that gains the electrons experiences a decrease in oxidation number.
For the reaction; CuCl2 + Zn → ZnCl2 + Cu
The oxidation half equation is;
Zn ------> Zn^2+ + 2e
The reduction half equation is;
Cu^2+ + 2e------> Cu
The chloride ion is excluded because its oxidation number does not change from left to right in the reaction.
Learn more: brainly.com/question/967776
Answer:
6.2g of NaBr are produced
Explanation:
The reaction of HBr with NaOH occurs as follows:
HBr + NaOH → NaBr + H2O
<em>Where 1 mole of each reactant produce 1 mole of NaBr</em>
To solve this question we need to find the moles of each reactant using their molar mass. With moles we can find limiting reactant and the moles (And mass) of NaBr produced, as follows:
<em>Moles HBr -Molar mass: 80.9119g/mol)-</em>
4.9g * (1mol/80.9119g) = 0.0606 moles HBr
<em>Moles NaOH -Molar mass: 40g/mol-</em>
3.86g * (1mol/40g) = 0.0965 moles NaOH
As the reaction is 1:1 and the moles of HBr < Moles NaOH, the limiting reactant is HBr and moles of NaBr produced are 0.0606 moles.
The mass of NaBr (Molar mass: 102.894g/mol) is:
0.0606 moles * (102.894g/mol) =
<h3>6.2g of NaBr are produced</h3>
