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Butoxors [25]
3 years ago
9

Read the false statement. Atoms of elements with one valence electron form anions in order to meet the octet rule. Which answer

choice rewords the false statement so it is true?
a. Atoms of elements with three valence electrons do not form ions because they meet the octet rule.
b. Atoms of elements with five to seven valence electrons form cations in order to meet the octet rule.
c. Atoms of elements with five to seven valence electrons form anions in order to meet the octet rule.
d. Atoms of elements with one valence electron gain seven electrons in order to meet the octet rule.
Chemistry
2 answers:
Zepler [3.9K]3 years ago
7 0

Answer:

C. Atoms of elements with five to seven valence electrons form anions in order to meet the octet rule.

Explanation:

  • Atoms of elements gain or lose electron(s) to obey the octet rule by forming cations or anions.
  • Atoms with 1 to 3 valence electrons lose electrons to form cations in order to attain a stable configuration.
  • Atoms with 5 to 7 valence electrons gain electron(s) to form anions in order to attain stable configuration.
  • However, atoms with 8 valence electrons do not require to gain or lose electrons since they an octet configuration.
  • Atoms of metallic elements such as those in group 1 and 2 lose electron(s) to form cations while atoms of non-metallic elements such as halogens require to gain electron(s) to form anions so as to obey the octet rule.
Inessa [10]3 years ago
6 0

Answer:

The correct statement is option C.

Explanation:

Octet rule: In a chemical bond each atom tends to have 8 electrons in their valence shell.

  • Atoms with one to three valence electrons in their valence shell tends to loose their electron to form a cation in order to meet octet rule.
  • Atoms with five to seven valence electrons in their valence shell tends to gain electron to form an anion in order to meet octet rule.

So, for atom with one valence electron gaining 7 electron more will be difficult. but is can easily loose its 1 electron to form a cation.

The correct statement comes out to be:

Atoms of elements with five to seven valence electrons form anions in order to meet the octet rule.

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3. Given 20g of Barium Hydroxide, how many grams of
anastassius [24]

The number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g

First, we will write the balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

Ba(OH)₂ + 2NH₄NO₃ → 2NH₄OH + Ba(NO₃)₂

This means, 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate

Now, we will calculate the number of moles of barium hydroxide present.

Mass of barium hydroxide (Ba(OH)₂) = 20 g

Using the formula

Number\ of\ moles = \frac{Mass}{Molar\ mass}

Molar mass of Ba(OH)₂ = 171.34 g/mol

∴ Number of moles of Ba(OH)₂ present =\frac{20}{171.34}

Number of moles of Ba(OH)₂ present = 0.116727 mole

Now,

Since 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate

Then,

0.116727 mole of barium hydroxide will react with 2 × 0.116727 mole of ammonium nitrate

2 × 0.116727 = 0.233454 mole

∴ Number of moles of NH₄NO₃ required is 0.233454 mole

Now, for the mass of ammonium nitrate (NH₄NO₃) required

From the formula

Mass = Number of moles × Molar mass

Molar mass of NH₄NO₃ = 80.043 g/mol

∴ Mass of NH₄NO₃ required = 0.233454 × 80.043

Mass of NH₄NO₃ required = 18.68636 g

Mass of NH₄NO₃ required ≅ 18.7g

Hence, the number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g

Learn more on determining mass of reactant required here: brainly.com/question/11232389

6 0
2 years ago
Which of the following elements has the highest electronegativity? beryllium iodine calcium nitrogen
juin [17]

Answer: Option (d) is the correct answer.

Explanation:

An atom or element which has the ability to readily gain an electron will have high electronegativity.

Both Beryllium and Calcium are alkaline earth metals and hence they are electropositive in nature.

Whereas both iodine and nitrogen are electronegative in nature. But across the period there is an increase in electronegativity and down the group there is a decrease in electronegativity.

Nitrogen belongs to period 2 and iodine belongs to the bottom of group 17. Thus, we can conclude that nitrogen is more electronegative than iodine.

8 0
3 years ago
Read 2 more answers
An atom of argon has a radius rar = 88 pm and an average speed in the gas phase at 25°C of 172 m/s.
Rudik [331]

Answer:

1.2* 10³ rNe.

Explanation:

Given speed of neon=350 m/s

Un-certainity in speed= (0.01/100) *350 =0.035 m/s

As per heisenberg uncertainity principle

Δx*mΔv ≥\frac{h}{4\pi }

4π

h

..................(1)

mass of neon atom =\frac{20*10^{-3} }{6.22*10^{-23} } =3.35*10^{-26} kg

6.22∗10

−23

20∗10

−3

=3.35∗10

−26

kg

substituating the values in eq. (1)

Δx =4.49*10^{-8}10

−8

m

In terms of rNe i.e 38 pm= 38*10^{-12}10

−12

Δx=\frac{4.49*10^{-8} }{38*10^{-12} }

38∗10

−12

4.49∗10

−8

=0.118*10^{4}10

4

* (rNe)

=1.18*10³ rN

= 1.2* 10³ rNe.

Explanation:

This is the answer

7 0
2 years ago
The shells further away from the nucleus are larger/smaller and can hold more/less electrons.
Sergeu [11.5K]
The shells further away from the nucleus are LARGER and can hold MORE electrons
8 0
2 years ago
Can someone help me find the theoretical value of methane? It is chemistry
antiseptic1488 [7]

Methane is lighter than air, having a specific gravity of 0.554. It is only slightly soluble in water. It burns readily in air, forming carbon dioxide and water vapour; the flame is pale, slightly luminous, and very hot. The boiling point of methane is −162 °C (−259.6 °F) and the melting point is −182.5 °C (−296.5 °F). Methane in general is very stable, but mixtures of methane and air, with the methane content between 5 and 14 percent by volume, are explosive. Explosions of such mixtures have been frequent in coal mines and collieries and have been the cause of many mine disasters.
8 0
3 years ago
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