Answer:
a. How much force is required to lift a box of weight 100 N upwards with a constant acceleration of 6.0 m/s2?
b. How much upwards force is required to lower the same box with a downward acceleration of 3.0 m/s2?
a. As the box weighs 100 N, its mass is 100 N / 9.8 ms-2 = 10.2 kg. To have an upward acceleration of 6.0 m/s2, there must be a net upward force of F =ma = 10.2 kg x 6.0 m/s2 = 61.2 N. The total upward force must be equal have a magnitude to overcome the downward force of gravity and to provide for the upward acceleration Ftotal up = 100 N + 61.2 N = 161.2 N.
b. There must be a net downward force F = ma = 10.2 kg x 3.0 m/s2 = 30.6 N upward. There must be an upward force to counteract the downward force of gravity so that the resultant will be 30.6 N. The equation necessary for this is 100 N - upward force = 30.6 N. Solving for the upward force gives 69.4 N.
Explanation:
Answer:
maximum work is done in the case
D) Clark pushed a crate from the chair, 16 meters across the room, doing 144 J of work.
Explanation:
As we know that the Work done is product of force and displacement
So we have
A) Steve put in 50 J of work moving a box 50 meters.
So here we have
50 = F . 50
F = 1 N
B) Doing 400 J of work, Penny pushed her cat 80 meters.
So here we have
400 = F . 80
F = 5 N
C) Samantha did 365 J of work dragging a wagon across 73 meters of lawn.
So here we have
365 = F . 73
F = 5 N
D) Clark pushed a crate from the chair, 16 meters across the room, doing 144 J of work.
So here we have
144 = F . 16
F = 9 N
So maximum work is done in the case
D) Clark pushed a crate from the chair, 16 meters across the room, doing 144 J of work.
<span>Ans: The source Address field specifies the station that sends the frame.
The format of an Ethernet frame includes a destination address at the beginning which contains the address of the device which is sending the frame. And, the source address tells us which station the information is received from. </span>
Answer:
Answer 1 = Google
Answer 2 = 42
Explanation:
Really, just google the words.
The 42 thing was a joke, but google 42.
935,500 joules because when we use the KE formula KE=1/2mv^2;
KE=1/2(750)(50)^2
KE=375(2500)
KE=935,500 Joules
Hope it helps