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PtichkaEL [24]
2 years ago
14

If I am lifting a box with a force of 100 N and the box has an acceleration of 10 N, what is the mass of the box?

Physics
1 answer:
Korolek [52]2 years ago
4 0

Answer:

a. How much force is required to lift a box of weight 100 N upwards with a constant acceleration of 6.0 m/s2?

b. How much upwards force is required to lower the same box with a downward acceleration of 3.0 m/s2?

a. As the box weighs 100 N, its mass is 100 N / 9.8 ms-2  =  10.2 kg.  To have an upward acceleration of 6.0 m/s2, there must be a net upward force of F =ma  =  10.2 kg x 6.0 m/s2 =  61.2 N.  The total upward force must be equal have a magnitude to overcome the downward force of gravity and to provide for the upward acceleration  Ftotal up = 100 N + 61.2 N  =  161.2 N.

b. There must be a net downward force F = ma = 10.2 kg x 3.0 m/s2  =  30.6 N upward.  There must be an upward force to counteract the downward force of gravity so that the resultant will be 30.6 N.  The equation necessary for this is 100 N - upward force =  30.6 N.  Solving for the upward force gives  69.4 N.

Explanation:

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Which statement describes the magnetic field inside a bar magnet?
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The statement that describes the magnetic field inside a bar magnet is as follows: it points from north to south.

<h3>What is a bar magnet?</h3>

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2 years ago
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Select the appropriate units for each property of a wave.
IceJOKER [234]

Intensity: Decibels

Amplitude: Meters

Frequency: Hertz

<u>Explanation:</u>

The Wave is not visible to eyes and they can easily propagate through vacuum. the average power travelling at a given period of time in a space is the intensity. Decibels is the measure of intensity. it is measured in the decibel scale. The wave's strength and the intensity gives the amplitude of wave. It is measured using meters.

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4 0
2 years ago
A car is rounding a 100-m-radius curve at 25 m/s.What is the minimum possible coefficient of static friction between the tires a
Crazy boy [7]

Answer:

The minimum possible coefficient of static friction between the tires and the ground is 0.64.

Explanation:

if the μ is the coefficient of static friction and R is radius of the curve and v is the speed of the car then, one thing we know is that along the curve, the frictional force, f will be equal to the centripedal force, Fc and this relation is :

Fc = f

m×(v^2)/(R) = μ×m×g

    (v^2)/(R) = g×μ

               μ = (v^2)/(R×g)

                  =  ((25)^2)/((100)×(9.8))

                  = 0.64

Therefore, the minimum possible coefficient of static friction between the tires and the ground is 0.64.

4 0
2 years ago
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