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3 years ago

If I am lifting a box with a force of 100 N and the box has an acceleration of 10 N, what is the mass of the box?

Physics

1 answer:

Korolek [52]3 years ago

4 0

Answer:

a. How much force is required to lift a box of weight 100 N upwards with a constant acceleration of 6.0 m/s2?

b. How much upwards force is required to lower the same box with a downward acceleration of 3.0 m/s2?

a. As the box weighs 100 N, its mass is 100 N / 9.8 ms-2 = 10.2 kg. To have an upward acceleration of 6.0 m/s2, there must be a net upward force of F =ma = 10.2 kg x 6.0 m/s2 = 61.2 N. The total upward force must be equal have a magnitude to overcome the downward force of gravity and to provide for the upward acceleration Ftotal up = 100 N + 61.2 N = 161.2 N.

b. There must be a net downward force F = ma = 10.2 kg x 3.0 m/s2 = 30.6 N upward. There must be an upward force to counteract the downward force of gravity so that the resultant will be 30.6 N. The equation necessary for this is 100 N - upward force = 30.6 N. Solving for the upward force gives 69.4 N.

Explanation:

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Evgen [1.6K]

Answer:

$\omega=0.24\ rad.s^{-1}$

Explanation:

Given:

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radius of merry go-round, $R=2\ m$

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We consider merry go-round as a ring:

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$\omega =$ angular velocity of the merry-go-round

$\omega_p=$ angular velocity of the person running

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