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3 years ago

5

When the frequency of a sound wave is doubled, then:

2 answers:

tresset_1 [31]3 years ago

6 0

Answer:

If the frequency of a wave is doubled, what happens to its wavelength? If the frequency is doubled, the wavelength is only half as long.

Leni [432]3 years ago

6 0

<h2>Answer:</h2>

<em>Hey, </em>

<h3><u>QUESTION)</u></h3>

<em>✔ We have : λ = v/f </em>

According to this relationship, the wavelength is inversely proportional to the frequency. So when the frequency doubles, the wavelength is halved.

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A man walks 400 m in the direction 45° north of east. Represent this vector graphically by

Marrrta [24]

Answer:

Explanation:

Coordinate system is one that describe the location of an object in a given plane. It implies the use of axes (coordinates) and points.

Given that the man in the question walks 400 m due north of east. The cardinal points can be used in this case, with the north and east cardinals as the required axis.

scale = $\frac{length on drawing}{original length}$

= $\frac{10}{400}$

= $\frac{1}{40}$

scale = 1:40

This is a reduced scale which implies that 1 cm on the drawing is equal to 40 m on the original length.

The man's direction is $45^{o}$ north of east.

The graphical drawing of the vector is herewith attached to this answer.

5 0

3 years ago

The equation below can be used to find the specific heat capacity of a substance. What is the specific

slavikrds [6]

Answer:

<em>specific</em><em> </em><em>heat</em><em> </em><em>capacity</em><em> </em><em>(</em><em>c</em><em>)</em><em> </em><em>=</em>107.2J/kg K

6 0

2 years ago

On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 81.7 cm and diameter 2.70 cm fr

Genrish500 [490]

Answer:

35.792 N

Explanation:

d = Diameter of rod = 2.7 cm

h = Length of rod = 81.7 cm

$\rho$ = Density of rod = 7800 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

Volume of rod

$V=\dfrac{1}{4}\pi d^2h\\\Rightarrow V=\dfrac{1}{4}\times \pi\times (2.7\times 10^{-2})^2\times 81.7\times 10^{-2}$

Mass is given by

$m=\rho V\\\Rightarrow m=7800\times \dfrac{1}{4}\times \pi\times (2.7\times 10^{-2})^2\times 81.7\times 10^{-2}\\\Rightarrow m=3.6486\ kg$

Weight is given by

$W=mg\\\Rightarrow W=3.6486\times 9.81\\\Rightarrow W=35.792\ N$

The weight of the rod is 35.792 N

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3 years ago

What is the energy in joules of a mole of photons associated with visible light of wavelength 486 nm?

Marrrta [24]

Answer:

$2.46\cdot 10^5 J$

Explanation:

The enegy of a single photon is given by:

$E=\frac{hc}{\lambda}$

where

h is the Planck costant

c is the speed of light

$\lambda$ is the wavelength of the photon

In this problem,

$\lambda=486 nm=4.86\cdot 10^{-7}m$

so the energy of one photon is

$E_1=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4.86\cdot 10^{-7}m}=4.09\cdot 10^{-19} J$

1 mole of photons contains a number of Avogadro of photons:

$N_A = 6.022\cdot 10^{23}$

therefore, the total energy of 1 mole of these photons will be

$E=N_A E_1 = (6.022\cdot 10^{23})(4.09\cdot 10^{-19} J)=2.46\cdot 10^5 J$

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4 years ago

A hockey player applied an average force of 80N to a 0.25kg hockey puck for a time of 0.2s. Determine the impulse experienced by

Nezavi [6.7K]

16 rgfggghffcccvghggg

7 0

3 years ago