Answer:
<em>D. 20 N</em>
Explanation:
<em>Force</em><em> </em><em>=</em><em> </em><em>mass(</em><em>m)</em><em> </em><em>×</em><em> </em><em>acceleration</em><em> due</em><em> to</em><em> </em><em>gravity (</em><em>g)</em>
<em>Force </em><em>=</em><em> </em><em>2</em><em>k</em><em>g</em><em> </em><em>×</em><em> </em><em>1</em><em>0</em><em>m</em><em>/</em><em>s²</em>
<em>Force</em><em> </em><em>=</em><em> </em><em>2</em><em>0</em><em>N</em>
The land form is formed by lava flows of low viscosity
Hope this helps! :)
The far side of the Moon is the hemisphere of the Moon that always faces away from Earth. The far side's terrain is rugged with a multitude of impact craters and relatively few flat lunar maria compared to the near side. It has one of the largest craters in the Solar System, the South Pole–Aitken basin.
Answer:
The charge-to-mass ratio of the particle is 5.7 × 10⁵ C/kg
Explanation:
From the formulae
F = qvB and F = mv²/r
Where F is Force
q is charge
v is speed
B is magnetic field strength
m is mass
and r is radius
Then,
qvB = mv²/r
qB = mv/r
We can write that
q/m = v/rB ---- (1)
Also
From Electric force formula
F = Eq
Where E is the electric field
and magnetic force formula
F = Bqv
Since, electric force = magnetic force
Then, Eq = Bqv
E = Bv
∴ v = E/B
Substitute v = E/B into equation (1)
q/m = (E/B)/rB
∴ q/m = E/rB²
(NOTE: q/m is the charge to mass ratio)
From the question,
E = 3.10 ×10³ N/C
r = 4.20 cm = 0.0420 m
B = 0.360 T
Hence,
q/m = 3.10 ×10³ / 0.0420 × (0.360)²
q/m = 569517.9306 C/kg
q/m = 5.7 × 10⁵ C/kg
Hence, the charge-to-mass ratio of the particle is 5.7 × 10⁵ C/kg.
