Question

On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 81.7 cm and diameter 2.70 cm from a storage room to a machinist. Calculate the weight of the rod, w. The acceleration due to gravity, g

Answer 1

Answer:

35.792 N

Explanation:

d = Diameter of rod = 2.7 cm

h = Length of rod = 81.7 cm

$\rho$ = Density of rod = 7800 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

Volume of rod

$V=\dfrac{1}{4}\pi d^2h\\\Rightarrow V=\dfrac{1}{4}\times \pi\times (2.7\times 10^{-2})^2\times 81.7\times 10^{-2}$

Mass is given by

$m=\rho V\\\Rightarrow m=7800\times \dfrac{1}{4}\times \pi\times (2.7\times 10^{-2})^2\times 81.7\times 10^{-2}\\\Rightarrow m=3.6486\ kg$

Weight is given by

$W=mg\\\Rightarrow W=3.6486\times 9.81\\\Rightarrow W=35.792\ N$

The weight of the rod is 35.792 N