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Oliga [24]
3 years ago
15

What are all the factors of 76

Mathematics
1 answer:
Len [333]3 years ago
7 0

Answer:

1, 2, 4, 19, 38, 76

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Please help, find AB
Rom4ik [11]
AB would equal 3.57 or 3.6 rounded as your directions ask because the sides are supposed to be proportional. When you do 21/5, you get 4.2. Then, you can just do 15/4.2 and get 3.57.
7 0
3 years ago
In baseball,the pitcher's mound is 60'6 feet from home plate,center field is 350' from home plate,and the distance between each
ahrayia [7]
This problem can be seen as a rectangle triangle where the vertices are:
 Vertice 1: home plate
 Vertice 2: First base
 Vertice 3: second base.
 Right angle between vertice 1 and 2 and vertice 2 and 3.
 Distance between each base in 90 '.
 Calculating then the distance between home plate and second base we have:
 d = root ((90) ^ 2 + (90) ^ 2)
 d = 127.28 feets
 answer:
 the distance between home plate and second base is 127.28 feets
3 0
3 years ago
The graph was made to compare the costs of taking two different taxis. What does the intersection mean for the two lines?
Bingel [31]

Answer: The total price of $8 is the same for both taxi cabs for 3 miles.

Step-by-step explanation: if you look at the graph you can see the dot on 8(which is the total cost) and the number of miles is 3

8 0
3 years ago
A baby weighed 7.25 pounds at birth. At the end of 8 months, the baby weighed 212
Vinil7 [7]

Answer:

1537pounds

Step-by-step explanation:

Given parameters:

  Weight of baby at birth  = 7.25 pounds

   

Unknown:

Weight at the end of 8months = ?

Solution:

 From the second sentence;

    Weight at the end of the eighth month = 212 x weight at birth.

Input the parameters and solve;

  Weight at the end of eighth month = 212 x  7.25  = 1537pounds

7 0
3 years ago
Grace wants to find the probability of a family of 3 children having 2 boys and 1 girl. Use a tree diagram to list the possibili
pychu [463]

Answer:

Step-by-step explanation:

My approach was to draw out the probabilities, since we have 3 children, and we are looking for 2 boys and 1 girl, the probabilities can be Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy. So a 2/3 chance if you think about it, your answer 2/3 can't be correct. If we assume that boys and girls are born with equal probability, then the probability to have two girls (and one boy) should be the same as the probability to have two boys and one girl. So you would have two cases with probability 2/3, giving an impossible 4/3 probability for both cases. Also, your list "Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy" seems strange. All of those are 2 boys and 1 girl, so based on that list, you should get a 100 percent chance. But what about Boy-Girl-Girl, or Girl-Girl-Girl? You get 2/3 if you assume that adjacencies in the (ordered) list are important, i.e., "2 boys and a girl" means that the girl was not born between the boys.

5 0
2 years ago
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