12 = 3/4 * x
12 ÷ 3/4 = x
12 * 4/3 = x
48/3 = x
16 = x
Answer: The whole set is 16 counters
Answer:
a-bi
Step-by-step explanation:
If a quadratic equation lx^2+mx+n=0 has one imaginary root as a+bi then the other root is the conjugate of a+bi = a-bi
Because we have l, m and n are real numbers and they are the coefficients.
Sum of roots = a+bi + second root = -m/l
When -m/l is real because the ratio of two real numbers, left side also has to be real.
Since bi is one imaginary term already there other root should have -bi in it so that the sum becomes real.
i.e. other root will be of the form c-bi for some real c.
Now product of roots = (a+bi)(c-bi) = n/l
Since right side is real, left side also must be real.
i.e.imaginary part =0
bi(a-c) =0
Or a =c
i.e. other root c-bi = a-bi
Hence proved.
You would have to use this equation : y2-y1/x2-x1 = slope
So it would be -13 +3/6-2= -10/4
Simplify it and you get : -5/2
Slope is -5/2
Answer: 3
Step-by-step explanation:
By the intersecting chords theorem,
Answer:
$110.37
Step-by-step explanation:
Assuming the monthly payment is made at the beginning of the month, the formula for the monthly payment P that gives future value A will be ...
... A = P(1+r/12)((1+r/12)^(nt) -1)/(r/12) . . . . n=compoundings/year, t=years
... 14000 = P(1+.11/12)((1+.11/12)^(12·7) -1)/(.11/12)
... 14000 = P(12.11)((1+.11/12)^84 -1)/0.11 ≈ P·126.84714 . . . . fill in the given values
... P = 14000/126.84714 = 110.37 . . . . . divide by the coefficient of P
They should deposit $110.37 at the beginning of each month.
