Help plz test !! Four more than the product of a number and 10 is at most the opposite of 12.

James has organised a game to raise money for charity at a local fair. He rolls a fair six sided dice and flips a fair coin. If

Scorpion4ik [409]

The total amount that was raised for charity is £75.

<h3>What is the total amount raised?</h3>

Here is the sample space

1 2 3 4 5 6

Heads 1 4 9 16 25 36

Tails 1 8 27 64 125 216

Probability of getting a number greater than 30 = 4/12 = 1/3

1/3 x 450 = 150

Total value of people getting more than 30 : 150 x £1 = £150

Total amount paid = 50 x 450 = £225

Amount raised = £225 - 150 = £75

To learn more about probability, please check: brainly.com/question/13234031

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3 0

2 years ago

Help me please i dont know what this is i cant think

GarryVolchara [31]

Answer:

ahhhhh swear that's scary honestly

8 0

2 years ago

132° 125° 141° 140° 145° r 120° 113° Find the value of R

Charra [1.4K]

Answer:

130*

Step-by-step explanation:

3 0

2 years ago

What's greater 3 fourths or 2 fourths

Len [333]

3 of anything positive is greater than 2 of the same thing.
I can't think of an exception.

7 0

3 years ago

Read 2 more answers

When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let

sergiy2304 [10]

Answer:

(a) P(X=3) = 0.093

(b) P(X≤3) = 0.966

(c) P(X≥4) = 0.034

(d) P(1≤X≤3) = 0.688

(e) The probability that none of the 25 boards is defective is 0.277.

(f) The expected value and standard deviation of X is 1.25 and 1.089 respectively.

Step-by-step explanation:

We are given that when circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%.

Let X = the number of defective boards in a random sample of size, n = 25

So, X ∼ Bin(25,0.05)

The probability distribution for the binomial distribution is given by;

$P(X=r)= \binom{n}{r} \times p^{r}\times (1-p)^{n-r} ; x = 0,1,2,......$

where, n = number of trials (samples) taken = 25

r = number of success

p = probability of success which in our question is percentage

of defectivs, i.e. 5%

(a) P(X = 3) = $\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $2300 \times 0.05^{3}\times 0.95^{22}$

= 0.093

(b) P(X $\leq$ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

= $\binom{25}{0} \times 0.05^{0}\times (1-0.05)^{25-0}+\binom{25}{1} \times 0.05^{1}\times (1-0.05)^{25-1}+\binom{25}{2} \times 0.05^{2}\times (1-0.05)^{25-2}+\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $1 \times 1 \times 0.95^{25}+25 \times 0.05^{1}\times 0.95^{24}+300 \times 0.05^{2}\times 0.95^{23}+2300 \times 0.05^{3}\times 0.95^{22}$

= 0.966

(c) P(X $\geq$ 4) = 1 - P(X < 4) = 1 - P(X $\leq$ 3)

= 1 - 0.966

= 0.034

(d) P(1 ≤ X ≤ 3) = P(X = 1) + P(X = 2) + P(X = 3)

= $\binom{25}{1} \times 0.05^{1}\times (1-0.05)^{25-1}+\binom{25}{2} \times 0.05^{2}\times (1-0.05)^{25-2}+\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$