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Alex Ar [27]
3 years ago
13

What is the equation for the perpendicular that passes through the point (-1,-2) ?

Mathematics
1 answer:
tangare [24]3 years ago
7 0

Answer:

Perpendicular with respects to what?

You can't find it with only a point, you also need a slope to know which line is which.

There are an infinite number of lines that go through any point. Each has a slope, without slopes, we cant solve such a question.

It's line asking, how old is Jane's dog?

Who knows man? There's like thousands of Janes, which one is the one?

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vampirchik [111]

Answer:

\large\boxed{x=\dfrac{-9\pm\sqrt{41}}{2}}

Step-by-step explanation:

\text{The quadratic formula of}

ax^2+bx+c=0

\text{If}\ b^2-4a0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\=========================================

\text{We have}\ x^2+9x+10=0\\\\a=1,\ b=9,\ c=10\\\\\text{substitute:}\\\\b^2-4ac=9^2-4(1)(10)=81-40=41>0\qquad _{\text{two solutions}}\\\\\sqrt{b^2-4ac}=\sqrt{41}\\\\x=\dfrac{-9\pm\sqrt{41}}{2(1)}=\dfrac{-9\pm\sqrt{41}}{2}

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