Answer:
Both are similar by SAS similarity.
This SAS similarity is equivalent to the congruence.
Step-by-step explanation:
Step 1:
To prove that ACB and HIG as similar triangles.
We have to look upon the corresponding sides.
SAS= Side angle sides , there the angle must be in between two sides.
ACB =
HIG
Lets work on the corresponding sides.
IG/AC = IH/AC
= 
Reducing each to lowest form, we divide numerator and denominator by 3 for the 1st fraction and by 4 for the 2nd fraction.
We have
= 
Both sides are equal.
So its proved that both are similar with SAS similarity theorem.
12.T
13.F
14.F
15.F.
16.???(where is 16?:O)
17.T
18.T
19.T
20.???(where is 20?)
21.5
22.5
Answer:
Domain: {x | x is all real numbers} Range: {y | y ≥ 6}
Step-by-step explanation:
Domain is the set of all x values. No operations restrict the domain in this case. The domain is all real numbers.
Range is the set of all y values. Absolute value has a v shape starting at 0. Adding 6 raises this vertex to 6. The range is therefore all numbers greater than or equal to 6.
Answer: It is TRUE. A point in a linear equation can be the solution to said equation.
Answer:
Step-by-step explanation:
It is convenient to memorize the trig functions of the "special angles" of 30°, 45°, 60°, as well as the way the signs of trig functions change in the different quadrants. Realizing that the (x, y) coordinates on the unit circle correspond to (cos(θ), sin(θ)) can make it somewhat easier.
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<h3>20.</h3>
You have memorized that cos(x) = (√3)/2 is true for x = 30°. That is the reference angle for the 2nd-quadrant angle 180° -30° = 150°, and for the 3rd-quadrant angle 180° +30° = 210°.
Cos(x) is negative in the 2nd and 3rd quadrants, so the angles you're looking for are
150° and 210°
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<h3>Bonus</h3>
You have memorized that sin(π/4) = √2/2, and that cos(3π/4) = -√2/2. The sum of these values is ...
√2/2 + (-√2/2) = 0
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<em>Additional comments</em>
Your calculator can help you with both of these problems.
The coordinates given on the attached unit circle chart are (cos(θ), sin(θ)).