1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rama09 [41]
3 years ago
5

Simplify. 7x + 3(x - 2) - 4x + 8Simplify. 7x + 3(x - 2) - 4x + 8. A) 6x+2 B) 6x+14 C) 6x-2 D) 14x+2

Mathematics
2 answers:
Paladinen [302]3 years ago
8 0

Answer:

A) 6x+2

Step-by-step explanation:

7x + 3(x - 2) - 4x + 8

Distribute the 3

7x + 3x - 6 - 4x + 8

Combine like terms

7x+3x-4x -6+8

6x +2

dedylja [7]3 years ago
4 0

A) 6X+2

step by step

7x+3x-6-4x+8

7x+3x-4x-6x+8

6x+2

You might be interested in
Pythagorean Theorem: Jason only has room for a TV that is less than 30” wide.
Tasya [4]

Answer:

No

Step-by-step explanation:

Using the Pythagorean Theorem, make 40 = c, 24 = b and the remaining side (the width) = a.

Solving for a we get a = \sqrt{c^2-b^2}. Then plugging in the values for c and b, we get a = \sqrt{1024} = 32

Since the width of the TV needs to be less than 30" wide, it will not fit since the width of the TV is 32" wide.

5 0
3 years ago
Read 2 more answers
a video store charges a one-time membership fee of $12.00 plus $1.50 per video rental. How many videos can stewart rent if he sp
Natasha_Volkova [10]
He could rent 6 videos if he spends $21.00
4 0
3 years ago
For what value of a should you solve the system of elimination?
SIZIF [17.4K]
\begin{bmatrix}3x+5y=10\\ 2x+ay=4\end{bmatrix}

\mathrm{Multiply\:}3x+5y=10\mathrm{\:by\:}2: 6x+10y=20
\mathrm{Multiply\:}2x+ay=4\mathrm{\:by\:}3: 3ay+6x=12

\begin{bmatrix}6x+10y=20\\ 6x+3ay=12\end{bmatrix}

6x + 3ay = 12
-
6x + 10y = 20
/
3a - 10y = -8

\begin{bmatrix}6x+10y=20\\ 3a-10y=-8\end{bmatrix}

3a-10y=-8 \ \textgreater \  \mathrm{Subtract\:}3a\mathrm{\:from\:both\:sides}
3a-10y-3a=-8-3a

\mathrm{Simplify} \ \textgreater \  -10y=-8-3a \ \textgreater \  \mathrm{Divide\:both\:sides\:by\:}-10
\frac{-10y}{-10}=-\frac{8}{-10}-\frac{3a}{-10}

Simplify more.

\frac{-10y}{-10} \ \textgreater \  \mathrm{Apply\:the\:fraction\:rule}: \frac{-a}{-b}=\frac{a}{b} \ \textgreater \  \frac{10y}{10}

\mathrm{Divide\:the\:numbers:}\:\frac{10}{10}=1 \ \textgreater \  y

-\frac{8}{-10}-\frac{3a}{-10} \ \textgreater \  \mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c} \ \textgreater \  \frac{-8-3a}{-10}

\mathrm{Apply\:the\:fraction\:rule}: \frac{a}{-b}=-\frac{a}{b} \ \textgreater \  -\frac{-3a-8}{10} \ \textgreater \  y=-\frac{-8-3a}{10}

\mathrm{For\:}6x+10y=20\mathrm{\:plug\:in\:}\ \:y=\frac{8}{10-3a} \ \textgreater \  6x+10\cdot \frac{8}{10-3a}=20

10\cdot \frac{8}{10-3a} \ \textgreater \  \mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \  \frac{8\cdot \:10}{10-3a}
\mathrm{Multiply\:the\:numbers:}\:8\cdot \:10=80 \ \textgreater \  \frac{80}{10-3a}

6x+\frac{80}{10-3a}=20 \ \textgreater \  \mathrm{Subtract\:}\frac{80}{10-3a}\mathrm{\:from\:both\:sides}
6x+\frac{80}{10-3a}-\frac{80}{10-3a}=20-\frac{80}{10-3a}

\mathrm{Simplify} \ \textgreater \  6x=20-\frac{80}{10-3a} \ \textgreater \  \mathrm{Divide\:both\:sides\:by\:}6 \ \textgreater \  \frac{6x}{6}=\frac{20}{6}-\frac{\frac{80}{10-3a}}{6}

\frac{6x}{6} \ \textgreater \  \mathrm{Divide\:the\:numbers:}\:\frac{6}{6}=1 \ \textgreater \  x

\frac{20}{6}-\frac{\frac{80}{10-3a}}{6} \ \textgreater \  \mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c} \ \textgreater \  \frac{20-\frac{80}{-3a+10}}{6}

20-\frac{80}{10-3a} \ \textgreater \  \mathrm{Convert\:element\:to\:fraction}: \:20=\frac{20}{1} \ \textgreater \  \frac{20}{1}-\frac{80}{-3a+10}

\mathrm{Find\:the\:least\:common\:denominator\:}1\cdot \left(-3a+10\right)=-3a+10

Adjust\:Fractions\:based\:on\:the\:LCD \ \textgreater \  \frac{20\left(-3a+10\right)}{-3a+10}-\frac{80}{-3a+10}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}: \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}
\frac{20\left(-3a+10\right)-80}{-3a+10} \ \textgreater \  \frac{\frac{20\left(-3a+10\right)-80}{-3a+10}}{6} \ \textgreater \  \mathrm{Apply\:the\:fraction\:rule}: \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}

20\left(-3a+10\right)-80 \ \textgreater \  Rewrite \ \textgreater \  20+10-3a-4\cdot \:20

\mathrm{Factor\:out\:common\:term\:}20 \ \textgreater \  20\left(-3a+10-4\right) \ \textgreater \  Factor\;more

10-3a-4 \ \textgreater \  \mathrm{Subtract\:the\:numbers:}\:10-4=6 \ \textgreater \  -3a+6 \ \textgreater \  Rewrite
-3a+2\cdot \:3

\mathrm{Factor\:out\:common\:term\:}3 \ \textgreater \  3\left(-a+2\right) \ \textgreater \  3\cdot \:20\left(-a+2\right) \ \textgreater \  Refine
60\left(-a+2\right)

\frac{60\left(-a+2\right)}{6\left(-3a+10\right)} \ \textgreater \  \mathrm{Divide\:the\:numbers:}\:\frac{60}{6}=10 \ \textgreater \  \frac{10\left(-a+2\right)}{\left(-3a+10\right)}

\mathrm{Remove\:parentheses}: \left(-a\right)=-a \ \textgreater \   \frac{10\left(-a+2\right)}{-3a+10}

Therefore\;our\;solutions\;are\; y=\frac{8}{10-3a},\:x=\frac{10\left(-a+2\right)}{-3a+10}

Hope this helps!
7 0
3 years ago
Read 2 more answers
Hi what is the answer to my question
Mashcka [7]

Answer:

594

Step-by-step explanation:

You multiply 18 by 3 by 11 :)

8 0
3 years ago
Read 2 more answers
Which graph is best to show categorical data?
dexar [7]

Answer:

Bar graphs, pie charts or circle graphs

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Other questions:
  • Lucy Baker is analyzing demographic characteristics of two television programs, American Idol (population 1) and 60 Minutes (pop
    7·1 answer
  • Estimate 0.482 x 61.2^2 ÷ square root of 98.01
    14·1 answer
  • Given: -1/4x > 4. Choose the solution set.
    9·1 answer
  • Fourth geometry question
    5·2 answers
  • What's the linear function for this
    11·1 answer
  • Plzzzzzzz Hallllpppppppppppppppppppp
    13·2 answers
  • Select &lt;, &gt;, or=.<br> 16 lb ? 240 oz
    11·1 answer
  • I think I know how to solve this, but could someone please check my work for me?
    14·1 answer
  • .<br> 1. Derek applies grass seed to 25 acre in 34 hour. How many acres can Derek cover per hour?
    10·1 answer
  • Are these triangle obtuse or acute using the pythagorean theorem?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!