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Minchanka [31]
2 years ago
14

Arrange in ascending order a) 2⁄5, -1⁄6, -11/30

Mathematics
1 answer:
nikitadnepr [17]2 years ago
8 0

Answer:

-11/30, -1/6, 2/5

Step-by-step explanation:

first, make the question in the same denominator

= 12/30, -5/30, -11/30

= -11/30, -5/30, 12/30

= -11/30, -1/6, 2/5

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Step-by-step explanation:

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8 0
3 years ago
I’ll give points + brainalist for correct answer (:
sweet-ann [11.9K]

Answer:

C) 2

Step-by-step explanation:

Emma: Range  = 8

Arianna: Range = 6

The difference in the range is 2 (8-6)

6 0
2 years ago
Read 2 more answers
Pls help with 29..tank you
trapecia [35]

Answer:

See below

Step-by-step explanation:

Let the  2 roots be  A and A^2.

Then A^3 = c/a and A + A^2 = -b/a.

Using the identity a^3 b^3 = (a + b)^3 - 3ab^2 - 3a^2b:-

A^3 + (A^2)^3 =  ( A + A^2)^3 - 3 A.A^4 - 3 A^2. A^2

= (A + A^2)^3 - 3A*3( A + A^2)

Substituting:-

c/a + c^2/a^2 = (-b/a)^3 - 3 (c/a)(-b/a)

Multiply through by a^3:-

a^2c + ac^2 = -b^3 + 3abc

Factoring:-

ac(a + c) = 3abc - b^3

This is not the formula required in the question but let's see if the formula in the question reduces to this. If it does we have completed the proof.

a(c - b)^3 = a(c^3 - 3c^2b + 3cb^2 - b^3) = ac^3 - 3ac^2b + 3acb^2 - ab^3

c(a - b)^3 = c(a^3 - 3a^2b + 3ab^2 - b^3) = ca^3 - 3a^2bc + 3acb^2 - cb^3.

These are equal so we have

ca^3 - 3a^2bc + 3acb^2 - cb^3 = ac^3 - 3abc^2 + 3acb^2 - ab^3

The 3acb^2 cancel out so we have:-

a^3c - ac^3 =  3a^2bc - 3abc^2 + b^3c - ab^3

ac(a^2 - c^2) = 3abc( a - c) + b^3(c - a)

ac(a + c)(a -c) = 3abc(a - c) - b^3 (a - c)

Divide through by (a - c):-

ac(a + c) = 3abc - b^3 , which is the result we got earlier.

This completes the proof.

 

3 0
3 years ago
Read 2 more answers
Can someone help me with this question: What is the 40th term of these sequences below. 13, 26, 39, 52,...... 6, 12, 18, 24,....
Nina [5.8K]

Answer:520; 240

Step-by-step explanation:

a. 13, 26, 39, 52,......

a = First term = 13

d = common difference = 26 - 13 = 13

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= 13 + (39 × 13)

= 13 + 507

= 520

b. 6, 12, 18, 24,.......

a = First term = 6

d = common difference = 12 - 6 = 6

40th term = a + 39d

= 6 + 39(6)

= 6 + 234.

= 240

8 0
2 years ago
Which conversion factors are used to convert 4km/min to meters per hour?
gladu [14]
I think your answer would be 4,000
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3 years ago
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