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sineoko [7]
3 years ago
15

A student has the following data recorded: final readings: 760. mm Hg, 6.0L, 197 'C. initial readings:

Chemistry
1 answer:
irina [24]3 years ago
7 0
Is that Geometry or Algebra?
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How much sucrose (g) do you need to weight in order to prepare 19.16 g of a 13.1 % (weight percent) solution?
Nonamiya [84]
<span>2.51 grams
   You want to prepare 19.16 g of some solution which will have 13.1% of it's mass being sucrose. So we just need to perform some simple multiplication: 19.16g * 0.131 = 2.50996g
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3 years ago
What is the mass of 2.50 moles of potassium chlorate in grams
Sedaia [141]

Answer: 306 grams are there in 2.50 moles of potassium chlorate

Explanation

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

given mass of potassium chlorate = ?

Molar mass of potassium chlorate = 122.55 g/mol

Putting in the values we get:

2.50=\frac{xg}{122.55g/mol}

x=2.50mol\times 122.55g/mol=306g

306 grams are there in 2.50 moles of potassium chlorate

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2Cu(s) + O2(g) --> 2CuO(s)
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Answer:

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