Answer: (i) F = 2
(ii) F = 3
(iii) F = 2
Explanation:
We would be applying the famous Gibbs Phase Rule to explaining this problem;
By applying the formula;
F+P = C +2
Where P = this represent the phase
F = this is called the degree of freedom
C = this represent the component in the system
Ok let us begin;
(i). from this we can see that there are 2 components i.e. (water + ethanol) and the phase in question is a vapor phase + liquid phase.
So from the formula;
F = C-P+2
F = 2 – 2 + 2 = 2
Therefore, F = 2.
(ii). Also, from the statement, we can figure there are 3 components, while the phases are two like the previous one above, i.e. liquid + vapor
F = 3 – 2 + 2 = 5 – 2 = 3
F = 3
(iii). From this statement, we can figure there are 3 components, and the phases are 3 i.e. (2 liquid phases + 1 vapor phase)
From the formula;
F = 3 – 3 + 2 = 0 + 2
F = 2
C. A lipid with three unsaturated fatty acids.
(got the question correct on a test)
While staying in the same period, if we move from left to right across the period, the atomic radius decreases. The reason is, in a period the number of shells remain the same and the number of electrons and protons increase as we move across the period to the right. The increased electrons and protons attract each other with greater force and hence the atomic size decreases.
So the element on the left most will have the largest atomic radius. So the correct ans is Potassium. Potassium will have the largest atomic size among Potassium, Calcium and Scandium.
Answer:
Ee your house 6r2f5r56rrrr6gjyf
Explanation:
Explanation:
mass H2O2 = 55 mL(1.407 g/mL) = 80.85 g
molar mass H2O2 = 2(1.01 g/mol) + 2(16.00 g/mol) = 34.02 g/mol
moles H2O2 = 80.85 g/34.02 g/mol = 2.377 moles H2O2
For each mole of H2O2 you obtain 0.5 mole of O2 (see the equation).
moles O2 = 2.377 moles H2O2 (1 mole O2)/(2 moles H2O2) = 1.188 moles O2
Now, you need the temperature. If you are at STP (273 K, and 1.00 atm) then 1 mole of an ideal gas at STP has a volume of 22.4 L. Without temperature you are not really able to continue. I will assume you are at STP.
Volume O2 = 1.188 moles O2(22.4 L/mole) = 0.0530 L of O2.
which is 53 mL.
