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2 years ago

What are the conditions that are required for electrical energy to be present in an electrical circuit?

Chemistry

1 answer:

Nat2105 [25]2 years ago

6 0

Answer:

a supply of electric charges which are free to flow, some form of push to move the charges through the circuit and a pathway to carry the charges.

Explanation:

There's your answer have a good day

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Identify the number of protons, neutrons, and electrons in a neutral atom of each of the following (you can refer to a periodic

Delvig [45]

You must first know that the number of protons and neutrons are same, and neutrons number may vary. Carbon 12 has 6 protons, 6 neutrons and 6 electrons. Sodium 23 has 12 protons , 12 electrons and and 11 neutrons. Silver 108 has 47 protons, 47 electrons and 61 electrons. Finally, Sulfur 32 has 16 protons, 16 nuetrons and 16 electrons. Basically the number of neutrons in an atom can be found by subtracting proton number from mass number

7 0

3 years ago

Please help! I'm not a smart 7th grader, on this assignment you write if it's convection, radiation, or conduction, then you wri

sattari [20]

#8 would be radiation
Because of the heat it produces for the air in the home
#9 Conduction
Because it’s preventing physical heat transfer
#10 convection
Because it is stopping the air from rising
#11 Radiation
Because the heat is emitting from the stove and warms him, but not by direct contact
#12 Conduction
Because the heat transfers from the top of the stove to the cats fur.
#13 Conduction
Because the stove under it heats it through contact
#14 I think Radiation
Because the heat warms up the dish through the air in the oven
#15 Radiation
Because the heat is emitting from the fire.
#16 Conduction
Because the blanket is warming you through physical contact.

I’m not completely sure but the is the best I got. Good luck!

6 0

4 years ago

the grade of coal increases with (remember a higher grade of coal means it produces more energy when burned) quizlet

Aleks04 [339]

The grade of coal increases with compaction.

<h3>What is Compaction?</h3>

When something is crushed or compressed, it becomes compacted. After being collected, trash is often compressed to make it smaller and take up less room. Compaction is the process of making anything more compact, dense, or firmly packed.

grade of coal - The highest grade of coal is anthracite. It is a black, glossy, hard, brittle coal that is frequently referred to as hard coal. It has a high proportion of fixed carbon and a low proportion of volatile matter. Between subbituminous and anthracite, bituminous coal is the intermediate rank of coal.

to learn more about compaction go to -

brainly.com/question/2837181

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5 0

1 year ago

A sample consisting of 1.00 mol of perfect gas molecules at 27 °C is expanded isothermally from an initial pressure of 3.00 atm

Evgesh-ka [11]

Answer:

a) reversibly

ΔU = 0

q = 2740.16 J

w = -2740.16 J

ΔH = 0

ΔS(total) = 0

ΔS(sys) =9.13 J/K

ΔS(surr) = -9.13 J/K

b) against a constant external pressure of 1.00 atm

ΔU = 0

w = -1.66 kJ

q = 1.66 kJ

ΔH = 0

ΔS(sys) = 9.13 J/K

ΔS(surr) = -5.543 J/K

ΔS(total) = 3.587 J/K

Explanation:

Step 1: Data given:

Number of moles = 1.00 mol

Temperature = 27.00 °C = 300 Kelvin

Initial pressure = 3.00 atm

Final pressure = 1.00 atm

The gas constant = 8.31 J/mol*K

(a) reversibly

Step 2: Calculate work done

For ideal gases ΔU depends only on temperature. So as it is an isothermal (T constant).

Since the temperature remains constant:

ΔU = 0

ΔU = q + w

q = -w

w = -nRT ln (Pi/Pf)

⇒ with n = the number of moles of perfect gas = 1.00 mol

⇒ with R = the gas constant = 8.314 J/mol*K

⇒ with T = the temperature = 300 Kelvin

⇒ with Pi = the initial pressure = 3.00 atm

⇒ with Pf = the final pressure = 1.00 atm

w =- 1*8.314 *300 * ln(3)

w = -2740.16 J

q = -w

q = 2740.16 J

Step 3: Calculate change in enthalpy

Since there is no change in energy, ΔH = 0

Step 4: Calculate ΔS

for an isothermal process

ΔS (total) = ΔS(sys) + ΔS(surr)

ΔS(sys) = -ΔS(surr)

ΔS(sys) = n*R*ln(pi/pf)

ΔS(sys) = 1.00 * 8.314 * ln(3)

ΔS(sys) = 9.13 J/K

ΔS(surr) = -9.13 J/K

ΔS (total) = ΔS(sys) + ΔS(surr) = 0

(b) against a constant external pressure of 1.00 atm

Step 1: Calculate the work done

w = -Pext*ΔV

w = -Pext*(Vf - Vi)

⇒ with Vf = the final volume

⇒ with Vi = the initial volume

We have to calculate the final and initial volume. We do this via the ideal gas law P*V=n*R*T

V = (n*R*T)/P

Initial volume = (n*R*T)/Pi

⇒ Vi = (1*0.08206 *300)/3

⇒ Vi = 8.206 L

Final volume = (n*R*T)/Pf

⇒ Vf = (1*0.08206 *300)/1

⇒ Vf = 24.618 L

The work done w = -Pext*(Vf - Vi)

w = -1.00* ( 24.618 - 8.206)

w = -16.412 atm*L

w = -16 .412 *(101325/1atm*L) *(1kJ/1000J)

w = -1662.9 J = -1.66 kJ

Step 2: Calculate the change in internal energy

ΔU = 0

q = -w

q = 1.66 kJ

ΔH = 0 because there is no change in energy

Step 3: Calculate ΔS

ΔS(sys) = n*R*ln(3)

ΔS(sys) = 1.00 * 8.314 * ln(3)

ΔS(sys) = 9.13 J/K

ΔS(surr) = -q/T

ΔS(surr) = -1662.9J/300K

ΔS(surr) = -5.543 J/K

ΔS(total) = ΔS(surr) +ΔS(sys) = -5.543 J/K + 9.13 J/K = 3.587 J/K

4 0

4 years ago

Convert 5.0x10^24 molecules to liters.

Over [174]

To convert the given value we need conversion factors to relate molecules to liters. At STP, we know that 1 mol is equal to 22.4 L and by using Avogadro's number we can relate molecules to 1 mol. Calculation is as follows:

5.0x10^24 molecules ( 1 mol / 6.022 x 10^23 molecules ) ( 22.4 L / 1 mol) = 186.0 L

3 0

3 years ago