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3 years ago

What is the slope of the line that passes through these two points (-2,4) (3,4)?

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

5 0

Answer:

Step-by-step explanation:

m=y-y1/x-x1

m=4-4/-2-3=0/-5

m=0

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Please solve, due tomorrow!

Darya [45]

5x=25 X= 5
X/3=7 X= 21
2x=14 X= 7
x/2=12 X=6
x/4=6 X=24

4 0

3 years ago

Please answer correctly !!!!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!!!

Digiron [165]

Answer:

x = 123°

General Formulas and Concepts:

<u>Geometry</u>

Corresponding Angles

Step-by-step explanation:

The angles on the transversal and parallel lines are Corresponding Angles. Therefore, according to the definition, they are congruent.

3 0

2 years ago

Solve the equation (1 + x²)dy +xydx= 0

Tatiana [17]

Answer:

$y=\frac{c}{\sqrt[]{x^2+1} }$

Step-by-step explanation:

(1 + x²)dy +xydx= 0

$(1+x^2)dy=-xydx\\\frac{1}{y}dy=\frac{-x}{x^2+1}dx\\$

Integrate both side

$lny=-\frac{1}{2} ln(x^2+1)+c\\y=\frac{c}{\sqrt[]{x^2+1} }$

7 0

3 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

3 years ago

Read 2 more answers

What is the value of x geometry PLSS HELPP

Bogdan [553]

The interior angle measures are 900 degrees
131+122+125+148+107+126 = 759
900-759 =141
X = 141

7 0

2 years ago